Ta có:
\(50\%x+\dfrac{2}{3}x=x+4\)
\(\Rightarrow\dfrac{1}{2}x+\dfrac{2}{3}x=x+4\)
\(\Rightarrow x\left(\dfrac{1}{2}+\dfrac{2}{3}\right)=x+4\)
\(\Rightarrow\dfrac{7}{6}x=x+4\)
\(\Rightarrow7x=6.\left(x+4\right)\)
\(\Rightarrow7x=6x+4\)
\(\Rightarrow x=4\)
Lời giải:
\(50\%x+\dfrac{2}{3}x=x+4\)
\(\dfrac{1}{2}x+\dfrac{2}{3}x=x+4\)
\(\Rightarrow\left(\dfrac{1}{2}+\dfrac{2}{3}\right)x=x+4\)
\(\Rightarrow\dfrac{7}{6}x=x+4\)
\(\Rightarrow\dfrac{7}{6}x-x=4\)
\(\Rightarrow\left(\dfrac{7}{6}-1\right)x=4\)
\(\Rightarrow\dfrac{1}{6}x=4\)
\(\Rightarrow x=4.6\)
\(\Rightarrow x=24\)