Question

Tìm x , biết:

\(^{4^{3x+1}}\) - 8. \(^{4^2}\) = 8.\(^{4^2}\)

b, \(^{7^{5x-1}}\) = \(^{7^4}\)

c, 14x - 2.\(^{7^2}\) = 2.3.7

d, \(^{2^3}\) + ( x-\(^{3^2}\) ) = \(^{2^6}\)

help me với

Answer 1

\(4^{3x+1}-8.4^2=8.4^2\)

\(\Rightarrow4^{3x}.4=8.4^2+8.4^2=16.4^2\)

\(\Rightarrow4^{3^x}=4.4.4=4^3\)

\(\Rightarrow3x=3\)

\(\Rightarrow x=1\)

Answer 2

\(7^{5x-1}=7^4\)

\(\Rightarrow5x-1=4\)

\(\Rightarrow5x=5\)

\(\Rightarrow x=1\)

Answer 3

\(14x-2.7^2=2.3.7\)

\(\Rightarrow7\left(2x-2.7\right)=2.3.7\)

\(\Rightarrow2x-2.7=2.3\)

\(\Rightarrow x-7=3\)

\(\Rightarrow x=10\)

Answer 4

\(2^3+\left(x-3^2\right)=2^6\)

\(\Rightarrow8+\left(x-9\right)=64\)

\(\Rightarrow x-1=64\)

\(\Rightarrow x=65\)