Ý bạn là: \(\left|\frac{2x-3}{4}\right|=4\frac{3}{4}\)
\(\Leftrightarrow\left|\frac{2x-3}{4}\right|=\frac{19}{4}\)
\(\Rightarrow\left[{}\begin{matrix}\frac{2x-3}{4}=\frac{19}{4}\\\frac{2x-3}{4}=-\frac{19}{4}=\frac{-19}{4}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=19\\2x-3=-19\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=11\\x=-8\end{matrix}\right.\)
Vậy: \(x\in\left\{11;-8\right\}\)
Đúng 0
Bình luận (0)
