Ôn tập toán 6
Các câu hỏi tương tự
\(a,-\dfrac{2}{3}.\left(x-\dfrac{1}{4}\right)=\dfrac{1}{3}.\left(2x-1\right)\)
\(b,\dfrac{1}{5}.2^x+\dfrac{1}{3}.2^{x+11}=\dfrac{1}{5}.2^7+\dfrac{1}{3}.2^8\)
\(c,\dfrac{x-19}{345}+\dfrac{x-20}{346}=\dfrac{x-1}{347}+\dfrac{x-22}{348}\)
tìm x:
a)\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
b) \(\left(x.6\dfrac{2}{7}+\dfrac{3}{7}\right).2\dfrac{1}{5}-\dfrac{3}{7}=-2\)
c) \(x.3\dfrac{1}{4}+\left(\dfrac{-7}{6}\right).x-1\dfrac{2}{3}=\dfrac{5}{12}\)
d) \(5\dfrac{8}{17}:x+\left(-\dfrac{4}{17}\right):x+3\dfrac{1}{7}:17\dfrac{1}{3}=\dfrac{4}{11}\)
Tìm x biết :
1/dfrac{4}{3} + x dfrac{2}{15} 2/dfrac{1}{3}+dfrac{1}{2}: x -0,25 3/(dfrac{2x}{5}+2 ):(-4) -1dfrac{1}{2} 4/ x.( x + 1) 0 5/3dfrac{1}{2}-dfrac{1}{2}x dfrac{2}{3}
6/1dfrac{1}{2}+xdfrac{3}{2}-7 7/2x-1640+x 8/x:dfrac{5}{3}+dfrac{1}{3}dfrac{-2}{5} 9/dfrac{x}{4}dfrac{9}{x}
Đọc tiếp
Tìm x biết :
1/\(\dfrac{4}{3}\) + x = \(\dfrac{2}{15}\) 2/\(\dfrac{1}{3}+\dfrac{1}{2}:\) x = -0,25 3/(\(\dfrac{2x}{5}+2\) ):(-4) = -1\(\dfrac{1}{2}\) 4/ x.( x + 1) = 0 5/3\(\dfrac{1}{2}-\dfrac{1}{2}x\) = \(\dfrac{2}{3}\)
6/1\(\dfrac{1}{2}+x=\dfrac{3}{2}-7\) 7/\(2x-16=40+x\) 8/\(x:\dfrac{5}{3}+\dfrac{1}{3}=\dfrac{-2}{5}\) 9/\(\dfrac{x}{4}=\dfrac{9}{x}\)
a, \(\dfrac{5}{2}-3\left(\dfrac{1}{3}-x\right)=\dfrac{1}{4}-7x\)
b,\(60\%.x+\dfrac{2}{3}.x=\dfrac{1}{3}.6\dfrac{1}{3}\)
c, \(\left(\dfrac{9}{2}.x-2x\right).\left(-1\dfrac{4}{7}\right)=\dfrac{11}{4}\)
d,\(\left(x+\dfrac{5}{6}\right).2\dfrac{2}{5}-1\dfrac{1}{4}=35\%\)
13 tháng 8 2017 lúc 14:30
tìm x
a,\(\dfrac{2}{3}x-\dfrac{5}{6}=1\dfrac{1}{4}\)
b,\(2\dfrac{1}{3}-\dfrac{4}{5}\div x=0,2\)
c,\(\dfrac{5}{6}-\dfrac{2}{3}x=0,2-1\dfrac{1}{4}x\)
d,\(\left(\dfrac{4}{3}-\dfrac{1}{4}x\right)^3=\dfrac{-8}{27}\)
giúp mình nhé mình đang cần gấp
25 tháng 8 2017 lúc 19:16
tìm x
a\(\dfrac{6}{7}x+\dfrac{5}{6}x=\dfrac{3}{4}\)
b\(\dfrac{5}{4}-\dfrac{3}{5}\div x=1\dfrac{1}{3}\)
c\(\left(\dfrac{4}{7}x-\dfrac{1}{3}\right)\div3\dfrac{1}{2}=0,5\)
d\(\dfrac{4}{5}-\dfrac{2}{3}x=1\dfrac{1}{4}+2,5x\)
giúp mình nhé mình đang cần gấp
tìm x biết
a) \(\dfrac{2x-3}{3}+-\dfrac{3}{2}=\dfrac{5-2x}{6}-\dfrac{1}{2}\)
b) \(\left(3x-\dfrac{1}{2}\right).\left(3-\dfrac{1}{2}x\right).\left(1+\dfrac{3}{4}:x\right)=0\)
c) \(\left(3-\dfrac{9}{10}-|x+2|\right):\left(\dfrac{19}{20}-1-\dfrac{2}{3}\right)+\dfrac{4}{5}=1\)
a, \(\dfrac{5}{2}-3\left(\dfrac{1}{3}-x\right)=\dfrac{1}{4}-7x\)
b, \(\left(1+\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2008}\right).x=\dfrac{2009}{1}+\dfrac{2010}{2}+...+\dfrac{5016}{2008}-2008\)
c, \(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{16}+...+\dfrac{2}{x.\left(x+1\right)}=\dfrac{2001}{2003}\)
GIÚP VỚI , MIK CẦN GẤP
21 tháng 8 2017 lúc 15:37
a\(\dfrac{5}{6}x-\dfrac{2}{3}=3\dfrac{1}{2}\)
b\(\dfrac{4}{5}-\dfrac{3}{4}\div x=0,3\)
c\(\dfrac{-3}{2}-\dfrac{1}{4}x=1\dfrac{1}{3}-0,2x\)
d\(\left|\dfrac{3}{5}x+\dfrac{4}{3}\right|:\dfrac{2}{3}-0,5=1\dfrac{1}{2}\)
e\(\dfrac{4x-5}{2-3x}=\dfrac{3}{4}\)
giúp mình nhé