Question

Tìm x:

a) \(\left|\dfrac{1}{2}-2x\right|\)=\(\dfrac{7}{2}\)

b) \(\dfrac{x}{3}=\dfrac{7}{12}+\dfrac{-1}{4}\)

Answer 1

avt của bn là anime fairy tail ak ?

Answer 2

wendy phải ko ?

Answer 3

a,x=-1,5 hoặc x=2

b,x=1

Answer 4

a) \(\left|\dfrac{1}{2}-2x\right|=\dfrac{7}{2}\)

\(\left|2x\right|=\dfrac{1}{2}-\dfrac{7}{2}\)

\(\left|2x\right|=-3\)

\(\Rightarrow\left[{}\begin{matrix}\left|2x\right|=-3\\\left|2x\right|=3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{-3}{2}\\x=\dfrac{3}{3}\end{matrix}\right.\)

b) \(\dfrac{x}{3}=\dfrac{7}{12}+\dfrac{-1}{4}\)

\(\dfrac{x}{3}=\dfrac{1}{3}\)

\(\Rightarrow x=1\)

Answer 5

a, \(\left|\dfrac{1}{2}-2x\right|=\dfrac{7}{2}\)

\(\Rightarrow\left[{}\begin{matrix}\dfrac{1}{2}-2x=\dfrac{7}{2}\\\dfrac{1}{2}-2x=\dfrac{-7}{2}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=-3\\2x=4\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{-3}{2}\\x=2\end{matrix}\right.\)

b, \(\dfrac{x}{3}=\dfrac{7}{12}+-\dfrac{1}{4}\)

\(\dfrac{x}{3}=\dfrac{1}{3}\)

=> x = 1

Answer 6

a,|1/2-2x|=7/2

1/2-2x=7/2 hoac 1/2-2x=-7/2

TH1 : 1/2-2x = 7/2

2x = 1/2 - 7/2

2x = -3

x = -3 : 2

x = -3/2

TH2: 1/2 - 2x = -7/2

2x = 1/2 - (-7/2)

2x = 1/2+7/2

2x = 4

x = 4 : 2

x = 2

Vay x = -3/2 hoac x = 2

Answer 7

b, x/3 = 7/12 + -1/4

x/3 = 7/12 + -3/12

x/3 = 1/3

suy ra x = 1

Vay x = 1