Question

tìm x

a) 7/18 . x - 2/3 = 5/18

b) 4/9 - 7/8 . x = -2/3

c) 1/6 + -5/7 : -7/18

/ là phần nha

Answer 1

a, \(\dfrac{7}{18}x-\dfrac{2}{3}=\dfrac{5}{18}\)

\(\dfrac{7}{18}x=\dfrac{5}{18}+\dfrac{2}{3}\)

\(\dfrac{7}{18}x=\dfrac{17}{18}\)

\(x=\dfrac{17}{18}\div\dfrac{7}{18}\)

\(x=\dfrac{17}{7}\)

Answer 2

a) \(\dfrac{7}{18}\).x-\(\dfrac{2}{3}\)=\(\dfrac{5}{18}\)

\(\dfrac{7}{18}\).x =\(\dfrac{5}{18}\)+\(\dfrac{2}{3}\)

\(\dfrac{7}{18}\).x = \(\dfrac{17}{18}\)

x = \(\dfrac{17}{18}\) :\(\dfrac{7}{18}\)

x =\(\dfrac{17}{7}\)

b)\(\dfrac{4}{9}\) - \(\dfrac{7}{8}\).x =\(\dfrac{-2}{3}\)

\(\dfrac{7}{8}\).x =\(\dfrac{4}{9}\)-\(\dfrac{-2}{3}\)

\(\dfrac{7}{8}\).x =\(\dfrac{10}{9}\)

x =\(\dfrac{10}{9}\) : \(\dfrac{7}{8}\)

x =\(\dfrac{80}{63}\)

c)\(\dfrac{1}{6}\)+\(\dfrac{-5}{7}\): \(\dfrac{-7}{18}\)

\(\dfrac{1}{6}\)+\(\dfrac{90}{49}\)

\(\dfrac{589}{294}\)

Answer 3

Nếu đúng mình xin 1 cái theo dõi nha bạn

Answer 4

a) \(\dfrac{7}{18}\).x -\(\dfrac{2}{3}\)= \(\dfrac{5}{18}\)

\(\dfrac{7}{18}\). x= \(\dfrac{5}{18}\)+\(\dfrac{2}{3}\)

\(\dfrac{7}{18}\). x= \(\dfrac{17}{18}\)

x= \(\dfrac{17}{18}\): \(\dfrac{7}{18}\)

x= \(\dfrac{68}{63}\)

Vậy x= \(\dfrac{68}{63}\)

b) \(\dfrac{4}{9}-\dfrac{7}{8}\). x=\(\dfrac{-2}{3}\)

\(\dfrac{7}{8}-x=\)\(\dfrac{4}{9}-\dfrac{-2}{3}\)

\(\dfrac{7}{8}\)- x= \(\dfrac{10}{9}\)

x=\(\dfrac{7}{8}-\dfrac{10}{9}\)

x=\(\dfrac{-17}{72}\)

Vậy x= \(\dfrac{-17}{72}\)

c) \(\dfrac{1}{6}\)+ \(\dfrac{-5}{7}\): \(\dfrac{-7}{18}\)

=\(\dfrac{1}{6}\)+ \(\dfrac{90}{49}\)

=\(\dfrac{589}{294}\)