Question

tim x:

a. \(3\dfrac{1}{3}x+16=13,25\)

b. \(x-43=\left(57-x\right)-50\)

Answer 1

a. \(3\dfrac{1}{3}x+16=13,25\)

=> x + 16 = 13,25

=> x = 13,25 - 16

=> x = \(-\dfrac{11}{4}\)

b. x - 43 = (57 - x) - 50

=> 2x = 57 - 50 + 43

=> 2x = 7 + 43

=> 2x = 50

=> x = 50 : 2

=> x = 25

Answer 2

a, \(3\dfrac{1}{3}x\) + 16 = 13,25

\(\dfrac{10}{3}x\) + 16 = 13,25

\(\dfrac{10}{3}x\) = -2,75

x = -2,75 : \(\dfrac{10}{3}\)

x = -\(\dfrac{33}{40}\)

b, x - 43 = ( 57 - x ) - 50

x - 43 = 57 - x - 50

x + x = 57 - 50 + 43

2x = 50

x = 25

Answer 3

a,\(3\dfrac{1}{3}x+16=13,25\)

\(\Rightarrow\dfrac{10}{3}x+16=\dfrac{53}{4}\)

\(\Rightarrow\dfrac{10}{3}x=\dfrac{53}{4}-16\)

\(\Rightarrow\dfrac{10}{3}x=-\dfrac{11}{4}\)

\(\Rightarrow x=-\dfrac{11}{4}\div\dfrac{10}{3}\)

\(\Rightarrow x=-\dfrac{33}{40}\)

vậy x\(=-\dfrac{33}{40}\)