Ta có:
\(\left(4x-1\right)^{30}=\left(4x-1\right)^{20}\)
Xét \(4x-1=0\)
\(\Rightarrow4x=1\Rightarrow x=\frac{1}{4}\), thỏa mãn
Xét \(4x-1\ne0\)
\(\Rightarrow\left(4x-1\right)^{30}:\left(4x-1\right)^{20}=1\)
\(\Rightarrow\left(4x-1\right)^{10}=1\Rightarrow\left[{}\begin{matrix}4x-1=1\Rightarrow x=\frac{1}{2}\\4x-1=-1\Rightarrow x=0\end{matrix}\right.\)
Vậy....