ta có : \(\left(3x-1\right)^3=125\Leftrightarrow\left(3x-1\right)^3=5^3\Rightarrow3x-1=5\)
\(\Leftrightarrow3x=5+1=6\Leftrightarrow x=\dfrac{6}{3}=2\) vậy \(x=2\)
ta có : \(x^{2010}=x\Leftrightarrow x^{2010}-x=0\Leftrightarrow x\left(x^{2009}-1\right)=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x^{2009}-1=0\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x^{2009}=1\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=1\end{matrix}\right.\) vậy \(x=0;x=1\)
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