\(2x+x=\frac{11}{12}\)
\(\Leftrightarrow3x=\frac{11}{12}\)
\(\Leftrightarrow x=\frac{11}{36}\)
Vậy...
Tìm x :
2x + x =
3x = \(\frac{11}{12}\)
x = \(\frac{11}{12}\) : 3
x = \(\frac{11}{36}\)
Tìm \(x\) :
2\(x\) + \(x\) = \(\frac{11}{12}\)
3\(x\) = \(\frac{11}{12}\)
\(x\) = \(\frac{11}{12}\) : 3
\(x\) = \(\frac{11}{36}\)
✰hok tốt✰
2x+x=\(\frac{11}{12}\)
=>3x=\(\frac{11}{12}\)
=>x=\(\frac{11}{12}\):3
=>x=\(\frac{11}{36}\)
\(2x+x=\frac{11}{12}\)\(\)
\(\Rightarrow3x=\frac{11}{12}\)
\(\Rightarrow x=\frac{11}{12}\div3\)
\(\Rightarrow x=\frac{11}{36}\)