\(\dfrac{-2}{5}-x=\dfrac{-3}{10}\)
\(x=\dfrac{-2}{5}-\dfrac{-3}{10}\)
\(x=\dfrac{-4}{10}-\dfrac{-3}{10}\)
\(x=\dfrac{-1}{10}\)
Vậy \(x=\dfrac{-1}{10}\)
\(\dfrac{-2}{5}\) - x = \(\dfrac{-3}{10}\)
=> x = \(\dfrac{-2}{5}\) - \(\dfrac{-3}{10}\)
=> x = \(\dfrac{-1}{10}\)
\(\dfrac{-2}{5}-x=\dfrac{-3}{10}\)
\(x=\dfrac{-2}{5}-\dfrac{-3}{10}\)
\(x=\dfrac{-1}{10}\)
\(\dfrac{-2}{5}\)\(-x=\dfrac{-3}{10}\)
\(x=\dfrac{-2}{5}-\dfrac{-3}{10}\)
\(x=\dfrac{-1}{10}\).
CHÚC BN HC TỐT!