11/5 + 3/5x = 3/4
3/5x = 3/4 - 11/5
3/5x = -29/20
x = -29/20 : 3/5
x = -29/12
\(\left(\dfrac{11}{5}+\dfrac{3}{5}x\right)=\dfrac{3}{4}\)
\(=\dfrac{3}{4}-\dfrac{11}{5}\)
\(=\dfrac{-29}{20}\)
\(=\dfrac{-29}{20}:\dfrac{3}{5}\)
\(=\dfrac{-29}{12}\)
Vậy x= \(\dfrac{-29}{12}\)