Question

Tìm sso tự nhiẽn x, biết:

a) 6 . x - 5 =613    b) 12 . (x-1) = 0

 

Answer 1

a) \(6x-5=613\)

\(\Leftrightarrow6x=618\Leftrightarrow x=103\)

b) \(12\left(x-1\right)=0\)

\(\Leftrightarrow x-1=0\Leftrightarrow x=1\)

 

Answer 2

a,6 .x-5=613

6x=613+5

6x=618

x=618:6

x=103

Answer 3

b,12.(x-1)=0

(x-1)=0:12

(x-1)=0

x=0+1

x=1

Answer 4

a)\( 6 . x - 5 =613 \)

\(\Rightarrow6x=613+5\)

\(\Rightarrow6x=618\)

\(\Rightarrow x=\dfrac{618}{6}\)

\(\Rightarrow x=103\)

Vậy \(x=103\)

b) \(12 . (x-1) = 0\)

\(\Rightarrow x-1=0\)

\(\Rightarrow x=1\)

Vậy \(x=1\)