a) \(2\left|x+1\right|=10\)
\(\Rightarrow\left|x+1\right|=5\)
\(\Rightarrow\left\{\begin{matrix}x+1=5\\x+1=-5\end{matrix}\right.\Rightarrow\left\{\begin{matrix}x=4\\x=-6\end{matrix}\right.\)
Vậy \(x\in\left\{4;-6\right\}\)
b) \(\left(-12\right)^2.x=56+10.13.x\)
\(\Rightarrow144x-130x=56\)
\(\Rightarrow14x=56\)
\(\Rightarrow x=4\)
Vậy x = 4