Ta có: \(\frac{4}{x}=\frac{y}{42}=\frac{28}{49}=\frac{-8}{z}\)
\(\Rightarrow\) \(\left[\begin{matrix}x=\frac{4.49}{28}\\y=\frac{42.28}{49}\\z=\frac{-8.49}{28}\end{matrix}\right.\)
\(\Rightarrow\) \(\left[\begin{matrix}x=\frac{196}{28}\\y=\frac{1176}{49}\\z=\frac{-392}{28}\end{matrix}\right.\)
\(\Rightarrow\) \(\left[\begin{matrix}x=7\\y=24\\z=-14\end{matrix}\right.\)
Vậy \(x=7;y=24;z=-14\).