*) \(-7+2x=-37-\left(-26\right)\)
⇔ \(-7+2x=-11\)
⇔ \(2x=\left(-11\right)-\left(-7\right)\)
⇔ \(2x=-4\)
⇔ \(x=\left(-4\right):2\)
⇔ \(x=-2\)
\(\text{(3x +9).(11-x ) =0}\)
⇔\(\left[{}\begin{matrix}3x+9=0\\11=x=0\end{matrix}\right.\)⇔\(\left[{}\begin{matrix}3x=-9\\x=11\end{matrix}\right.\)⇔\(\left[{}\begin{matrix}x=-3\\x=11\end{matrix}\right.\)
Vậy x= -3 và x= 11
(3x +9).(11-x ) =0(3x +9).(11-x ) =0
⇔[3x+9=011=x=0[3x+9=011=x=0⇔[3x=−9x=11[3x=−9x=11⇔[x=−3x=11[x=−3x=11
Vậy x= -3 và x= 11
