Ta có:
15abc : abc = `101
(15000 +abc) : abc = 101
15000 : abc + abc : abc = 101
15000 : abc + 1 = 101
15000 : abc = 100
abc = 15000 : 100
abc = 150
Vậy số dó là 150
Theo đề ta có :
\(\overline{15abc}:\overline{abc}=101\)
\(\Rightarrow\overline{15abc}=101.\overline{abc}\)
Có : \(\overline{15abc}=10000+5000+100a+10b+c=15000+\overline{abc}\)
\(\Rightarrow15000+\overline{abc}=101.\overline{abc}\)
\(\Rightarrow15000=101.\overline{abc}-\overline{abc}\)
\(\Rightarrow15000=\overline{abc}.\left(101-1\right)\)
\(\Rightarrow15000=\overline{abc}.100\)
\(\Rightarrow\overline{abc}=15000:100=150\)
Tick mik nhé!
À mình bị nhầm đề nha
Làm lại:
Ta có:
\(\overline{15abc}:\overline{abc}=101\)
\(\Rightarrow\left(15000+\overline{abc}\right):\overline{abc}=101\)
\(\Rightarrow15000:\overline{abc}+\overline{abc}:\overline{abc}=101\)
\(\Rightarrow15000:\overline{abc}+\overline{abc}:\overline{abc}=101\)
\(\Rightarrow15000:\overline{abc}+1=101\)
\(\Rightarrow15000:\overline{abc}=100\)
\(\Rightarrow\overline{abc}=150\)
Đề bị sai nha
\(15abc:abc=101\Rightarrow15=101\) (Vô lý)
