Question

tìm các cặp số nguyên x và y biết

a, ( x + 3 ) ( y + 2 ) = 1

b, ( x - 1 ) ( x + y ) = 33

c, ( 2x - 5 ) ( y - 6 ) = 17

d, ( x - 2 ) ^ 2 * ( y - 3 ) = -14

Answer 1

a) \(\left(x+3\right)\left(y+2\right)=1\)

\(\Rightarrow\left[\begin{matrix}x+3=1\\y+2=1\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=-2\\y=-1\end{matrix}\right.\)

b) \(\left(x-1\right)\left(x+y\right)=33\)

\(\Rightarrow x-1=33\Rightarrow x=34\)

\(\Rightarrow\left(34-1\right)\left(34+y\right)=33\)

\(=33.\left(34+y\right)=33\)

\(\Rightarrow34+y=33:33\)

\(34+y=1\Rightarrow y=35\)

Vậy : \(\left[\begin{matrix}x=34\\y=35\end{matrix}\right.\)

Answer 2

b) \(\left(x-1\right)\left(x+y\right)=33\)

\(\Rightarrow x-1=33\Rightarrow x=34\)

\(33.\left(34+y\right)=33\)

\(\Rightarrow34+y=33:33\)

\(34+y=1\Rightarrow y=-33\)

Vậy : \(\left[\begin{matrix}x=34\\y=-33\end{matrix}\right.\)

Answer 3

2 bài còn lại mình chưa biết