a, \(x+5=3\)
\(\Leftrightarrow x=3-5\)
\(\Leftrightarrow x=-2\)
Vậy ....
b, \(12x-64=2^5\)
\(\Leftrightarrow12x-64=32\)
\(\Leftrightarrow12x=32+64\)
\(\Leftrightarrow12x=96\)
\(\Leftrightarrow x=96:12\)
\(\Leftrightarrow x=8\)
Vậy ..
a,\(x+5=3\)
\(x=-2\)
b,\(12x-64=2^5\)
\(12x-64=32\)
\(12x=96\)
\(x=8\)
A,x+5=3
x=3-5
x=-2
B,12x-64=25
12x-64=32
12x=32+64
12x=96
x=96:12
x=8