Câu hỏi của Lê Quốc Khánh

Question

Tìm a,b,c thuộc Z

a+b+c+d=1

a+c+d=2

a+b+d=3

a+b+c=4

Y_Duyên_Trần · Accepted Answer

a+b+c+d=1; a+c+d=2

=> b=-1

a+b+c+d=1; a+b+d=3

=> c=-2

a+b+c+d=1; a+b+c=4

=> d=-3

Suy ra a = 7.

Vậy a = 7, b=-1, c=-2, d=-3.Câu trả lời: a+b+c+d=1; a+c+d=2

=> b=-1

a+b+c+d=1; a+b+d=3

=> c=-2

a+b+c+d=1; a+b+c=4

=> d=-3

Suy ra a = 7.

Vậy a = 7, b=-1, c=-2, d=-3.

Nguyễn Hạnh · Answer

Ta có:

$b=\left(a+b+c+d\right)-\left(a+c+d\right)\rightarrow b=1-2=-1$

$c=\left(a+b+c+d\right)-\left(a+b+d\right)\rightarrow c=1-3=-2$

$d=\left(a+b+c+d\right)-\left(a+b+c\right)\rightarrow d=1-4=-3$

$a=-1+-2+-3=1\rightarrow a=1-\left(-3\right)-\left(-2\right)-\left(-1\right)=7$Câu trả lời: Ta có:

$b=\left(a+b+c+d\right)-\left(a+c+d\right)\rightarrow b=1-2=-1$

$c=\left(a+b+c+d\right)-\left(a+b+d\right)\rightarrow c=1-3=-2$

$d=\left(a+b+c+d\right)-\left(a+b+c\right)\rightarrow d=1-4=-3$

$a=-1+-2+-3=1\rightarrow a=1-\left(-3\right)-\left(-2\right)-\left(-1\right)=7$

phuongenglish · Answer

Ta có:

b=(a+b+c+d)−(a+c+d)→b=1−2=−1

c=(a+b+c+d)−(a+b+d)→c=1−3=−2

d=(a+b+c+d)−(a+b+c)→d=1−4=−3

a+ (−1) +(−2)+(−3)=1→a=1−(−3)−(−2)−(−1)$\rightarrow$ a= 1+3+2+1=7

Vậy $\left\{{}\begin{matrix}a=7\b=-1\c=-2\d=-3\end{matrix}\right.$Câu trả lời: Ta có:

b=(a+b+c+d)−(a+c+d)→b=1−2=−1

c=(a+b+c+d)−(a+b+d)→c=1−3=−2

d=(a+b+c+d)−(a+b+c)→d=1−4=−3

a+ (−1) +(−2)+(−3)=1→a=1−(−3)−(−2)−(−1)$\rightarrow$ a= 1+3+2+1=7

Vậy $\left\{{}\begin{matrix}a=7\b=-1\c=-2\d=-3\end{matrix}\right.$

Chương II : Số nguyên