\(A=\dfrac{1,6:\left(1\dfrac{3}{5}.1,25\right)}{0,64-\dfrac{1}{25}}+\dfrac{\left(1,08-\dfrac{2}{25}\right):\dfrac{4}{7}}{5\dfrac{5}{9}-2\dfrac{1}{4}.2\dfrac{2}{17}}+0,6.0,5:\dfrac{2}{5}\)
\(A=\dfrac{\dfrac{8}{5}:\left(\dfrac{8}{5}.\dfrac{5}{4}\right)}{\dfrac{64}{100}-\dfrac{4}{100}}+\dfrac{\left(\dfrac{108}{100}-\dfrac{8}{100}\right):\dfrac{4}{7}}{\left(\dfrac{50}{9}-\dfrac{9}{4}\right).\dfrac{36}{17}}+\dfrac{3.1.5}{5.2.2}\)
\(A=\dfrac{\dfrac{4}{5}}{\dfrac{60}{100}}+\dfrac{1:\dfrac{4}{7}}{\left(\dfrac{200}{36}-\dfrac{81}{36}\right).\dfrac{36}{17}}+\dfrac{3}{4}\)
\(A=\dfrac{\dfrac{4}{5}}{\dfrac{3}{5}}+\dfrac{\dfrac{7}{4}}{\dfrac{119}{36}.\dfrac{36}{17}}+\dfrac{3}{4}\)
\(A=\dfrac{4}{3}+\dfrac{\dfrac{7}{4}}{7}+\dfrac{3}{4}\)
\(A=\dfrac{16}{12}+\dfrac{3}{12}+\dfrac{9}{12}\)
\(A=\dfrac{28}{12}\) \(=\dfrac{7}{3}\)
