Ta có:\(\dfrac{16}{9}\)=\(\dfrac{208}{117}\) \(\dfrac{24}{13}=\dfrac{216}{117}\)
Vì\(\dfrac{208}{117}< \dfrac{216}{117}nên\)\(\dfrac{16}{9}< \dfrac{24}{13}\)
Chúc bạn học tốt ạ
Ta có:\(\dfrac{16}{9}\)=\(\dfrac{208}{117}\) \(\dfrac{24}{13}=\dfrac{216}{117}\)
Vì\(\dfrac{208}{117}< \dfrac{216}{117}nên\)\(\dfrac{16}{9}< \dfrac{24}{13}\)
Chúc bạn học tốt ạ
\(\dfrac{-5}{9}+1\dfrac{5}{9}\cdot\left(\dfrac{3}{4}-\dfrac{2}{5}\right):7^2\)
\(1\dfrac{13}{15}\cdot0,75-\left(\dfrac{104}{195}+25\%\right)\cdot\dfrac{24}{47}-3\dfrac{12}{13}:3\)
\(1\dfrac{13}{15}\cdot\left(0,5\right)^2\cdot3+\left(\dfrac{8}{15}+1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(\dfrac{3}{4}.\dfrac{8}{9}.\dfrac{15}{16}.\dfrac{24}{25}._{......}.\dfrac{80}{81}.\dfrac{99}{100}\)
I tính
1,\(\dfrac{3}{4}.\dfrac{8}{9}.\dfrac{15}{16}.\dfrac{24}{25}.\dfrac{35}{36}.\dfrac{48}{49}.\dfrac{63}{64}\)
2, 1,2+2,3+......+8,9+9,10+10,11+......+98,99+100,101+......+998,999
3, 1,2+2,4+3,6+4,8+5,10+6,12+....+45,90
4, 1,1+1,11+1,111+......+1,111....11+1,11111....111
(9 số 1) (10 so 1)
Tính A = \(\dfrac{8}{9}.\dfrac{15}{16}.\dfrac{24}{25}...\dfrac{2499}{2500}\)
bài 1 : so sánh :
a) \(\dfrac{23}{21}\)và\(\dfrac{21}{23}\)
b)\(\dfrac{19}{26}\)và \(\dfrac{21}{25}\)
bài 2 : sắp sếp các phân số sau từ bé đến lớn :
a)\(\dfrac{7}{36};\dfrac{24}{36};\dfrac{13}{36};\dfrac{1}{36};\dfrac{43}{36};\dfrac{36}{36}\)
b)\(\dfrac{-3}{10};\dfrac{-31}{100};\dfrac{-297}{1000};\dfrac{10000}{-3056}\)
c)\(\dfrac{13}{20};\dfrac{7}{20};\dfrac{9}{4};\dfrac{2}{5};\dfrac{1}{2}\)
d)\(\dfrac{13}{21};\dfrac{152}{17};\dfrac{13}{17};\dfrac{-5}{21}\)
e)\(\dfrac{-1}{2};\dfrac{3}{-4};\dfrac{-2}{3};\dfrac{4}{-5}\)
tính nhanh
A=\(\dfrac{3}{2^2}.\dfrac{8}{3^2}.\dfrac{15}{4^2}...\dfrac{899}{30^2}\)
B=\(\dfrac{8}{9}.\dfrac{15}{16}.\dfrac{24}{25}...\dfrac{2499}{2500}\)
Tính :
a) \(\dfrac{17}{23}.\dfrac{8}{16}.\dfrac{23}{17}.\left(-80\right).\dfrac{3}{4}\)
b) \(\dfrac{5}{11}.\dfrac{18}{29}-\dfrac{5}{11}.\dfrac{8}{29}+\dfrac{5}{11}.\dfrac{19}{29}\)
c) \(\left(\dfrac{13}{23}+\dfrac{1313}{2323}-\dfrac{131313}{232323}\right).\left(\dfrac{1}{3}+\dfrac{1}{4}-\dfrac{7}{12}\right)\)
d) \(\dfrac{1^2}{1.2}.\dfrac{2^{2^{ }}}{2.3}.\dfrac{3^2}{3.4}.\dfrac{4^2}{4.5}.\dfrac{5^2}{5.6}.\dfrac{6^2}{6.7}.\dfrac{7^2}{7.8}.\dfrac{8^2}{8.9}.\dfrac{9^2}{9.10}\)
e) \(\dfrac{2^2}{3}.\dfrac{3^2}{8}.\dfrac{4^2}{15}.\dfrac{5^2}{24}.\dfrac{6^2}{35}\dfrac{7^2}{48}.\dfrac{8^2}{63}.\dfrac{9^2}{80}\)
tính
\(\dfrac{-5}{8}:\dfrac{15}{4}\) \(\dfrac{-15}{17}:\dfrac{25}{-34}\) \(-48:(\dfrac{-24}{5})\) \(\dfrac{-30}{7}:(\dfrac{-5}{-14})\)
\(\dfrac{15}{28}:(\dfrac{-9}{14})\) \(\dfrac{-7}{40}:(-\dfrac{21}{20})\) \((\dfrac{-4}{15}).(-\dfrac{-25}{8})\) \(\dfrac{5}{-14}.(-\dfrac{7}{10})\)
\(\dfrac{-15}{4}.(-\dfrac{16}{25})\) \(15.(-\dfrac{13}{10})\) \((-\dfrac{14}{5}).-10\) \((\dfrac{3}{-10}).(-\dfrac{-15}{2})\)
A=15.\(\left(\dfrac{3}{5}-\dfrac{2}{3}\right)+1\)
\(B=1-\dfrac{13}{9}:\dfrac{8}{19}+\dfrac{-11}{9}:\dfrac{8}{19}\)
\(C=\dfrac{-5}{7}.\dfrac{2}{11}+\dfrac{-5}{7}.\dfrac{9}{11}+1\dfrac{5}{7}\)
\(D=\dfrac{6}{7}+\dfrac{5}{8}:5-\dfrac{3}{16}.\left(-2\right)^2\)
tính giá trị của biểu thức