ta thấy:
\(A=\dfrac{37^{20}}{37^{20}-6}< \dfrac{37^{20}+4}{37^{20}-6}< \dfrac{37^{20}+4}{37^{20}-2}\)
\(\Rightarrow A< \dfrac{37^{20}+4}{37^{20}-2}\)
vậy...
ta thấy:
\(A=\dfrac{37^{20}}{37^{20}-6}< \dfrac{37^{20}+4}{37^{20}-6}< \dfrac{37^{20}+4}{37^{20}-2}\)
\(\Rightarrow A< \dfrac{37^{20}+4}{37^{20}-2}\)
vậy...
Thực hiện phép tính một cách hợp lý :
a) \(\dfrac{-12}{7}\) . \(\dfrac{4}{35}\) + \(\dfrac{12}{7}\) . \(\dfrac{-31}{35}\) - \(\dfrac{2}{7}\)
b) 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + ... + 97 + 98 - 99 - 100.
c) A = 157 . ( - 37 ) - ( 41 . 53 - 37 . 157 ) + 51 . 53
d) B = \(\left(\dfrac{1}{11}+\dfrac{1}{21}+\dfrac{1}{31}+\dfrac{1}{41}+\dfrac{1}{51}\right)\) \(\left(\dfrac{-41}{123}+\dfrac{31}{-186}-\dfrac{-51}{102}\right)\)
Bài1. (4điểm) Thực hiện phép tính:
a) \(A=\dfrac{3}{5}+6\dfrac{5}{6}\left(11\dfrac{5}{20}-9\dfrac{1}{4}\right):8\dfrac{1}{3}\)
b) \(B=\dfrac{-1}{2}+\dfrac{-1}{6}+\dfrac{-1}{12}+\dfrac{-1}{20}+\dfrac{-1}{30}+\dfrac{-1}{42}+\dfrac{-1}{56}+\dfrac{-1}{72}+\dfrac{-1}{90}\)
Bài 1: So sánh
a) A=\(\dfrac{13^{15}+1}{13^{16}+1}\) và B=\(\dfrac{13^{16}+1}{13^{17}+1}\)
b) C=\(\dfrac{1999^{1999}+1}{1999^{2000}+1}\) và D=\(\dfrac{1999^{1998}+1}{1999^{1999}+1}\)
Bài 2: So sánh các ps sau một cách hợp lý
a) \(\dfrac{29}{33};\dfrac{22}{37};\dfrac{29}{37}\)
b) \(\dfrac{163}{257};\dfrac{163}{221};\dfrac{149}{257}\)
Bài 4: so sánh biểu thức A và B
a) A=\(\dfrac{19}{41}+\dfrac{23}{53}+\dfrac{29}{61}\)
B=\(\dfrac{21}{41}+\dfrac{23}{49}+\dfrac{33}{65}\)
b) C=\(\dfrac{19^{20}+5}{19^{20}-8}vàD=\dfrac{19^{21}+6}{19^{21}-7}\)
1. tìm x, y\(\in Z\) biết:
a) x . y = -20
b) (2x-1).(4y+2)=-30
2. tìm giá trị lớn nhất của biểu thức: P=\(-\left(2x-6\right)^2-\left|-5-y\right|+37\)
Bài 2. Tính nhanh
a) 27 + (-2019) + (-27)
d) (-102) – (345 – 102)
b) (-10) + 23 + (-20) + 30
e) (12 + 34 – 56) – (12 – 56)
c) (-2).125.(-5).(-8).(+17) f) 37.(-345) – 345.(-47)
1. Tìm x, biết:
a, \(1\dfrac{3}{5}\) + \(\dfrac{\dfrac{2}{7}+\dfrac{2}{17}+\dfrac{2}{37}}{\dfrac{5}{7}+\dfrac{5}{17}+\dfrac{5}{37}}\) . x = \(\dfrac{16}{5}\)
b, (\(\dfrac{1}{24.25}\) + \(\dfrac{1}{25.26}\) + . . . + \(\dfrac{1}{39.40}\) ) . 120 + x. \(\dfrac{1}{3}\) = -4
c, \(\left|x-\dfrac{1}{3}\right|\) . 2 + \(\dfrac{4}{5}\) = 0,24
d, \(\dfrac{24}{7x-3}\) = \(\dfrac{-4}{25}\)
e, ( 50% x + \(5\dfrac{1}{4}\) ) , \(\dfrac{-2}{3}\) = \(2\dfrac{5}{6}\)
f, \(1\dfrac{1}{3}\) - 25%\(\dfrac{-5}{12}\) + 2x = 1,6 : \(\dfrac{3}{5}\)
CMR \(1-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{19}-\dfrac{1}{20}=\dfrac{1}{11}+\dfrac{1}{12}+\dfrac{1}{13}+...+\dfrac{1}{20}\)
Cho M= 2012^37+37^2012+1/2012^38 và N= 2012^38+37^2012+2/2012^39. So sánh M và N