\(A=\dfrac{10^8+2}{10^8-1}=\dfrac{10^8-1+3}{10^8-1}=\dfrac{10^8-1}{10^8-1}+\dfrac{3}{10^8-1}=1+\dfrac{3}{10^8-1}\)
\(B=\dfrac{10^8}{10^8-3}=\dfrac{10^8-3+3}{10^8-3}=\dfrac{10^8-3}{10^8-3}+\dfrac{3}{10^8-3}=1+\dfrac{3}{10^8-3}\)
Vì \(\dfrac{3}{10^8-1}< \dfrac{3}{10^8-3}\)
Nên \(1+\dfrac{3}{10^8-1}< 1+\dfrac{3}{10^8-3}\)
Vậy A < B.
Cho \(A=\dfrac{10^8+2}{10^8-1}\)và \(B=\dfrac{10^8}{10^8-3}\). So sánh A và B ?
So sánh A và B :
a) \(A=\dfrac{20}{39}+\dfrac{22}{27}+\dfrac{18}{43}\)
\(B=\dfrac{14}{39}+\dfrac{22}{29}+\dfrac{18}{41}\)
b) \(A=\dfrac{3}{8^3}+\dfrac{7}{8^4}\)
\(B=\dfrac{7}{8^3}+\dfrac{3}{8^4}\)
c) \(A=\dfrac{10^7+5}{10^7-8}\)
\(B=\dfrac{10^8+6}{10^8-7}\)
d) \(A=\dfrac{10^{1992}+1}{10^{1991}+1}\)
\(B=\dfrac{10^{1993}+1}{10^{1992}+1}\)
Cho A=\(\dfrac{10^7+1}{10^8+ 1}\)
B=\(\dfrac{10^8+1}{10^9+1}\)
So sánh
A=\(\dfrac{10^{15}-9}{10^{15}-3}\)
và B=\(\dfrac{10^{16}-8}{10^{16}-2}\)
bài 1 : so sánh phân số sau:
a) \(\dfrac{18}{91}\)và\(\dfrac{23}{114}\)
b)\(\dfrac{21}{52}\)và\(\dfrac{213}{523}\)
bài 2:so sánh
a)\(\dfrac{n}{n+1}\)và\(\dfrac{n+2}{n+3}\)
b)\(\dfrac{n}{n+3}\)và\(\dfrac{n-1}{n+4}\)
c)\(\dfrac{n}{2n+1}\)và \(\dfrac{3n+1}{6n+3}\)
bài 3: so sánh A và B
a)\(A=\dfrac{20}{39}+\dfrac{22}{27}+\dfrac{18}{43}\)
\(B=\dfrac{14}{39}+\dfrac{22}{29}+\dfrac{18}{14}\)
b)\(A=\dfrac{10^{1992}+1}{10^{1991}+1}\)
\(B=\dfrac{10^{1993}+1}{10^{1992}+1}\)
c)\(A=\dfrac{10^7+5}{10^7-8}\)
\(B=\dfrac{10^8+6}{10^8-7}\)
\(A=1-2+2^2-2^3+2^4-2^5+...+2^{2016}\)
\(B=\left(1+\dfrac{8}{10}\right).\left(1+\dfrac{8}{22}\right).\left(1+\dfrac{8}{36}\right)...\left(1+\dfrac{8}{8352}\right)\)
Tính rồi tìm số nghịch đảo của :
\(\dfrac{2}{3}.\dfrac{4}{5}.\dfrac{6}{7}.\dfrac{8}{9}.\dfrac{10}{11}.\dfrac{1}{2}.\dfrac{3}{4}.\dfrac{5}{6}.\dfrac{7}{8}.\dfrac{9}{10}\)
So sánh: A=108+2/108-1 và B=108/108-3
Giúp mình với!!!!!!!!!!! Help me!!!!!!!!!!!!!!!!
So sánh 2 số A=(2^5)^8 . 4^10 và B= 2^0 .4^10 .8^12.16
