+) Nếu x-2=0 =>x=2
+) Nếu x2-4=0 => x=2 hoặc x= -2
+) Nếu 3x-9=0 => x=3
+) Nếu x3+8=0 =>x= - 2
Vậy để biểu thức bằng 0 thì x=2 ; x=-2 ; x=3
A=\(\frac{\left(1^3+2^3+3^3+...+10^3\right)\cdot\left(x^2+y^2\right)\cdot\left(x^3+y^3\right)\cdot\left(x^4+y^4\right)}{1^2+2^2+3^2+...+10^2}\)
Tinh gia tri bieu thuc
\(\left(x-3\right)\cdot\left(y-2\right)=7\)
\(\left(x-1\right)\cdot\left(y-1\right)=2\)
\(\left(x-1\right)\cdot\left(y-2\right)=2\)
Bài 1:Tính
a, A=\(\dfrac{3}{4}\cdot\dfrac{8}{9}\cdot\dfrac{15}{16}\cdot....\cdot\dfrac{9999}{10000}\)
b,B=\(\left(1-\dfrac{1}{21}\right)\cdot\left(1-\dfrac{1}{28}\right)\cdot\left(1-\dfrac{1}{36}\right)\cdot....\cdot\left(1-\dfrac{1}{1326}\right)\)
c,C=\(\left(1+\dfrac{1}{1\cdot3}\right)\cdot\left(1+\dfrac{1}{2\cdot4}\right)\cdot\left(1+\dfrac{1}{3\cdot5}\right)\cdot....\cdot\left(1+\dfrac{1}{99\cdot101}\right)\)
1)tìm x
a)\(\dfrac{2}{3}x+\dfrac{5}{7}=\dfrac{3}{10}\) b)\(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\) c)\(2\cdot\left(2x-\dfrac{1}{7}\right)=0\) d)\(\left(3-2x\right)\left(7x-\dfrac{1}{8}\right)=0\)
2)xác định giá trị của để:
a)\(\dfrac{x+3}{x-5}\)có giá trị âm b)\(\left(x+\dfrac{2}{3}\right)\cdot\left(x-2\right)>0\)
giúp mình !
Tìm x
a ) \(15-3\cdot x=6\) b)\(\dfrac{2}{3}-\dfrac{4}{3}\cdot x=\dfrac{1}{2}\) c) \(3^{19}\cdot\left(x-12\right)=4\cdot3^{20}\) d) \(3\cdot\left(x-4\right)=2^2\cdot3^3\)
\(\dfrac{-5}{9}+1\dfrac{5}{9}\cdot\left(\dfrac{3}{4}-\dfrac{2}{5}\right):7^2\)
\(1\dfrac{13}{15}\cdot0,75-\left(\dfrac{104}{195}+25\%\right)\cdot\dfrac{24}{47}-3\dfrac{12}{13}:3\)
\(1\dfrac{13}{15}\cdot\left(0,5\right)^2\cdot3+\left(\dfrac{8}{15}+1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
Tìm x, y ϵ N biết
a, \(x\cdot y+8=x+y\)
b,\(\left(5x+7\right)\) chia hết cho \(x-2\)
c,\(2x\cdot\left(y-3\right)=y+2\)
\(A=\left(1-\dfrac{1}{2}\right)\cdot1-\dfrac{1}{3}\cdot......\cdot\left(1-\dfrac{1}{2016}\right)\cdot\left(1-\dfrac{1}{2017}\right)\)
