\(B=\frac{10}{56}+\frac{10}{140}+\frac{10}{260}+...+\frac{10}{1400}\)
\(\Rightarrow B=\frac{5}{28}+\frac{5}{70}+\frac{5}{130}+...+\frac{5}{700}\)
\(\Rightarrow\frac{3B}{5}=\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+...+\frac{3}{25.28}\)
\(\Rightarrow\frac{3B}{5}=\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{25}-\frac{1}{28}\)
\(\Rightarrow\frac{3B}{5}=\frac{1}{4}-\frac{1}{28}\)
\(\Rightarrow\frac{3B}{5}=\frac{3}{14}\)
\(\Rightarrow B=\frac{3}{14}.\frac{5}{3}\)
\(\Rightarrow B=\frac{5}{14}\)
Vậy \(B=\frac{5}{14}\)