\(P=\dfrac{\dfrac{2}{3}-\dfrac{1}{4}+\dfrac{5}{11}}{\dfrac{5}{12}+1-\dfrac{7}{11}}=\dfrac{\dfrac{88}{132}-\dfrac{33}{132}+\dfrac{60}{132}}{\dfrac{55}{132}+\dfrac{132}{132}-\dfrac{84}{132}}=\dfrac{\dfrac{88-33+60}{132}}{\dfrac{55+132-84}{132}}=\dfrac{\dfrac{115}{132}}{\dfrac{103}{132}}=\dfrac{115}{132}\cdot\dfrac{132}{103}=\dfrac{115}{103}\)Vậy P=\(\dfrac{115}{103}\).
\(P=\dfrac{\dfrac{2}{3}-\dfrac{1}{4}+\dfrac{5}{11}}{\dfrac{5}{12}+1-\dfrac{7}{11}}\)
Cho \(A=\dfrac{2}{3}-\dfrac{1}{4}+\dfrac{5}{11}\)
\(A=\dfrac{5}{12}+\dfrac{5}{11}\)
\(A=\dfrac{115}{132}\)
Cho \(B=\dfrac{5}{12}+1-\dfrac{7}{11}\)
\(B=\dfrac{17}{12}-\dfrac{7}{11}\)
\(B=\dfrac{103}{132}\)
\(P=\dfrac{A}{B}\)
\(\Rightarrow P=\dfrac{115}{132}:\dfrac{103}{132}\)
\(\Rightarrow P=\dfrac{115}{103}\)
