số la mã hay giá trị tuyệt đối đấy?
Bài đây không cần giải vì tớ ghi để sai
MONG CÁC BẠN THÔNG CẢM
Bài 1: Tính:
A=\(\left(-2\right).\left(-3\right)-5.\left|-5\right|+125.\left(\dfrac{-1}{5}\right)^2\)
B=\(\left(-3\right).\left|-7\right|-\left(-4\right).\left|5\right|+\dfrac{1}{3}.\left|-9\right|\)
C=\(\left(-2\right)^3.\left|-3\right|-\dfrac{1}{5}.\left|-25\right|-4.\left|-7\right|+\left(-2\right)^2\)
D=\(\left(-6\right).\left|-3\right|+2.\left|-9\right|-7\left|\left(-2\right)^3\right|+8.\left|-7\right|\)
E=\(\left|-3^2\right|.\left|4\right|-\left|7\right|.8-\left|6\right|.\left|-8\right|-\left|12\right|.\left(\dfrac{1}{2}\right)^2\)
Bài 2: Tìm x:
a)\(12-2\left|3x+2\right|=10\)
b)\(2.\left|5-4x\right|+17=\left(-2\right)^3.\left(-4\right)\)
c)\(\left|3x-5\right|+\left(-3\right)^2.2=12.\left|3x+5\right|+117\)
d)\(4.\left|3-2x\right|+\left(-5\right).\left|4-3x\right|-5=-6\)
e)\(\left|2x-7\right|-2^3.\left|2x-7\right|+15=-5.\left|2x-7\right|+3\)
f)\(\left|x+2\right|+\left|x^2-4\right|=0\)
g)\(\left|3x-9\right|+\left|x^2-9\right|=0\)
h)\(\left|2x-1\right|+\left|x^2-\dfrac{1}{4}\right|=0\)
a) \(56+\left(-29\right)+\left(-7\right)+28+13+\left(-35\right)\)
b) \(\left(-213\right)+186+\left(-14\right)+217+54+\left(-49\right)\)
c)\(435+\left(-43\right)+\left(-483\right)+\left(-57\right)+383+\left(-415\right)\)
Tính A = \(\left|-3\right|+\left|-2\right|+\left|-1\right|+\left|1\right|+\left|2\right|+\left|3\right|\)
Làm thế nào z
So sánh P với Q biết :
\(P=a-\left\{\left(a-3\right)-[\left(a-3\right)-\left(-a-2\right)\right\}]\)
\(Q=\left[a+\left(a+3\right)\right]-\left[\left(a+2\right)-\left(a-2\right)\right]\)
2.Tính:
A=\(\left(\dfrac{1}{10}-1\right).\left(\dfrac{1}{11}-1\right)\left(\dfrac{1}{12}-1\right).....\left(\dfrac{1}{100}-1\right)\)
B=\(\left(1-\dfrac{1}{2^2}\right)\left(1-\dfrac{1}{3^2}\right)\left(1-\dfrac{1}{10^2}\right)\)
C=\(\left(\dfrac{7}{9}+1\right)\left(\dfrac{7}{20}+1\right)\left(\dfrac{7}{33}+1\right)...\left(\dfrac{7}{108080}+1\right)\)
D=\(\left(1-\dfrac{28}{10}\right)\left(1-\dfrac{52}{22}\right)\left(1-\dfrac{80}{36}\right)...\left(1-\dfrac{21808}{10900}\right)\)
Rút gọn biểu thức:
a) \(M=\left(71+x\right)-\left(-24-x\right)+\left(-35-x\right)\)
b) \(x-34-\left[\left(15+x\right)-\left(23-x\right)\right]\)
c) \(\left(-15+\left|x\right|\right)+\left(25-\left|x\right|\right)\)
Giúp mình nha
Tính:
\(M=\frac{\left(1+17\right)\left(1+\frac{17}{2}\right)\left(1+\frac{17}{3}\right)........\left(1+\frac{17}{19}\right)}{\left(1+19\right)\left(1+\frac{19}{2}\right)\left(1+\frac{19}{3}\right)........\left(1+\frac{19}{17}\right)}\)
Thực hiện phép tính
m) \(-\left|-5\right|+\left(-19\right)+18+\left|11-4\right|-57\)
n) \(126+\left(-20\right)+\left|124\right|-\left(-320\right)-\left|-150\right|\)
\(\frac{\left[\left(e-m\right)^2-\left(e+m^2\right)\right].\left[\left(y-1\right)^2-\left(y+1\right)^2\right]}{a.16.n.h}x\frac{ê}{u^{-1}}\)
\(\frac{3}{\left(x+2\right).\left(x+5\right)}\) +\(\frac{5}{\left(x+5\right).\left(x+10\right)}\) + \(\frac{7}{\left(x+10\right).\left(x+5\right)}\)= \(\frac{x}{\left(x+2\right).\left(x+17\right)}\)
