Question

\(\left|12x+8\right|\) +\(\left|11y-5\right|\) \(\le\) =0

Answer 1

Ta thấy: \(\left\{\begin{matrix}\left|12x+8\right|\ge0\\\left|11y-5\right|\ge0\end{matrix}\right.\)

\(\Rightarrow\left|12x+8\right|+\left|11y-5\right|\ge0\)

Mà \(\left|12x+8\right|+\left|11y-5\right|\le0\)

Suy ra dấu "=" xảy ra khi và chỉ khi

\(\left\{\begin{matrix}\left|12x+8\right|=0\\\left|11y-5\right|=0\end{matrix}\right.\)\(\Rightarrow\left\{\begin{matrix}12x+8=0\\11y-5=0\end{matrix}\right.\)\(\Rightarrow\left\{\begin{matrix}12x=-8\\11y=5\end{matrix}\right.\)\(\Rightarrow\left\{\begin{matrix}x=-\frac{8}{12}\\y=\frac{5}{11}\end{matrix}\right.\)