\(\dfrac{8}{9}+\dfrac{1}{3}=\dfrac{8}{9}+\dfrac{3}{9}=\dfrac{11}{9}\)
\(\dfrac{3}{4}-\dfrac{1}{2}=\dfrac{3}{4}-\dfrac{2}{4}=\dfrac{1}{4}\)
\(\dfrac{7}{18}-\dfrac{1}{3}=\dfrac{7}{18}-\dfrac{6}{18}=\dfrac{1}{18}\)
\(\dfrac{2}{3}-\dfrac{7}{12}=\dfrac{8}{12}-\dfrac{7}{12}=\dfrac{1}{12}\)
\(\dfrac{4}{6}+\dfrac{1}{12}=\dfrac{2}{3}+\dfrac{1}{12}=\dfrac{8}{12}+\dfrac{1}{12}=\dfrac{9}{12}=\dfrac{3}{4}\)
\(\dfrac{19}{20}-\dfrac{3}{4}=\dfrac{19}{20}-\dfrac{15}{20}=\dfrac{4}{20}=\dfrac{1}{5}\)
\(\dfrac{9}{12}+\dfrac{3}{4}=\dfrac{3}{4}+\dfrac{3}{4}=\dfrac{6}{4}=\dfrac{3}{2}\)
\(\dfrac{1}{5}+\dfrac{2}{10}=\dfrac{1}{5}+\dfrac{1}{5}=\dfrac{2}{5}\)
\(\dfrac{4}{5}-\dfrac{2}{15}=\dfrac{12}{15}-\dfrac{2}{15}=\dfrac{10}{15}=\dfrac{2}{3}\)
\(\dfrac{9}{18}+\dfrac{1}{2}=\dfrac{1}{2}+\dfrac{1}{2}=1\)