Question

Giúp

Answer 1

? 

Answer 2

???

đb

Answer 3

???

Answer 4

woe bài :V

Answer 5

vio thì ko nên lm

Answer 6

đâu

Answer 7

bài giề

ko có bài giúp cái nịt

Answer 8

??

Answer 9

bài?

Answer 10

Ta có:

100A=\(\dfrac{100^{2022}+100}{100^{2022}+1}\); 100B=\(\dfrac{100^{2021}+100}{100^{2021}+1}\)

100A=\(\dfrac{100^{2022}+1+99}{100^{2022}+1}\); 100B=\(\dfrac{100^{2021}+1+99}{100^{2021}+1}\)

100A=1+\(\dfrac{99}{100^{2022}+1}\);100B=1+\(\dfrac{99}{100^{2021}+1}\)

Ta có:\(100^{2022}+1\)>\(100^{2021}+1\)

=>\(\dfrac{99}{100^{2022}+1}\)<\(\dfrac{99}{100^{2021}+1}\)

=>\(\dfrac{100^{2022}+100}{100^{2022}+1}\)<\(\dfrac{100^{2021}+100}{100^{2021}+1}\)

=>100A<100B

=>A<B

Answer 11

a >b 

----hết----