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Question

Giúp mình tí :

x+(x+1)+(x+2)+......+(x+100)=5051

Quìn · Accepted Answer

$x+\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5051$

$\Rightarrow x.101+\left(1+2+...+100\right)=5051$

$\Rightarrow x.101+5050=5051$

$\Rightarrow x.101=5051-5050$

$\Rightarrow x.101=1$

$\Rightarrow x=1:101$

$\Rightarrow x=1$

Vậy $x=1$Câu trả lời: $x+\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5051$

$\Rightarrow x.101+\left(1+2+...+100\right)=5051$

$\Rightarrow x.101+5050=5051$

$\Rightarrow x.101=5051-5050$

$\Rightarrow x.101=1$

$\Rightarrow x=1:101$

$\Rightarrow x=1$

Vậy $x=1$

Đường Lam Khuê · Answer

x+ (x+1)+ (x+2) +...+(x+100) = 5051

$\Rightarrow$ 101x +(1+2+3+...+100) = 5051

$\Rightarrow$  101x + [(101. 100): 2]  = 5051

$\Rightarrow$  101x  + 5050                 = 5051

$\Rightarrow$ 101x                               = 5051-5050

$\Rightarrow$ 101x                               = 1

$\Rightarrow$       x                               = 1: 101 = $\dfrac{1}{101}$Câu trả lời: x+ (x+1)+ (x+2) +...+(x+100) = 5051

$\Rightarrow$ 101x +(1+2+3+...+100) = 5051

$\Rightarrow$  101x + [(101. 100): 2]  = 5051

$\Rightarrow$  101x  + 5050                 = 5051

$\Rightarrow$ 101x                               = 5051-5050

$\Rightarrow$ 101x                               = 1

$\Rightarrow$       x                               = 1: 101 = $\dfrac{1}{101}$

Chương III : Phân số