Bài 1:
\(\dfrac{4}{3}-\dfrac{1}{3}\cdot\dfrac{5}{2}=\dfrac{8}{6}-\dfrac{5}{6}=\dfrac{1}{2}\)
\(\left(\dfrac{3}{2}-\dfrac{3}{8}\right):\dfrac{1}{2}=\dfrac{3\cdot8-3}{8}\cdot2=\dfrac{24-3}{4}=\dfrac{21}{4}\)
\(\dfrac{15}{16}\cdot\dfrac{8}{3}\cdot\dfrac{3}{4}=\dfrac{15}{16}\cdot2=\dfrac{15}{8}\)
\(\dfrac{7}{19}\cdot\dfrac{1}{3}+\dfrac{7}{19}\cdot\dfrac{2}{3}=\dfrac{7}{19}\cdot\left(\dfrac{1}{3}+\dfrac{2}{3}\right)=\dfrac{7}{19}\)
\(\dfrac{3}{5}\cdot\dfrac{8}{27}\cdot\dfrac{25}{3}=\dfrac{25}{5}\cdot\dfrac{8}{27}=\dfrac{40}{27}\)
\(\dfrac{1}{5}+\dfrac{4}{11}+\dfrac{4}{5}+\dfrac{7}{11}=1+1=2\)