\(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{12}{14}\)
K)\(\frac{7}{5}\)x-\(\frac{1}{4}\)=\(\frac{—5}{11}\)x
I)\(\frac{5}{7}\)x+\(\frac{7}{13}\)x=\(\frac{4}{3}\)
Tính
a, A= \(\left(\frac{3}{5}\right)^2.5^2-\left(2\frac{1}{4}\right)^3:\left(\frac{3}{4}\right)^3+\frac{1}{2}\)
b, B= \(\left[\frac{4}{11}.\left(\frac{1}{25}\right)^0+\frac{7}{22}.2\right]^{2010}-\left(\frac{1}{2^2}:\frac{8^2}{4^4}\right)^{2009}\)
Giải hộ bài này giúp mik nhé
Cho:
\(A=4+\frac{1}{7^6}+\frac{3}{7}+\frac{4}{7^2}+\frac{-441}{7^6}+\frac{27}{7^5}\)
\(B=\frac{147}{7}+4+\frac{35}{7^7}+\frac{4}{7^2}+\frac{27}{7^5}+\frac{-9}{7^9}\)
Hãy so sánh A với B
Tính nhanh:
\(A=\dfrac{1}{2\cdot5}+\dfrac{1}{5\cdot8}+\dfrac{1}{8\cdot11}+...+\dfrac{1}{92\cdot95}+\dfrac{1}{95\cdot98}\)
(cảm ơn nhiều ạa)
Bài 1:Tìm x biết Bài 2:So sánh
a, \(x+\frac{1}{2}=\frac{3}{8}.\frac{4}{5}\) a, \(A=\frac{10^{10}-1}{10^{11}-1}vaB=\frac{10^9-1}{10^{10}-1}\)
b, \(\frac{5}{16}:x-\frac{1}{4}=\frac{5}{8}\) b, B =\(\frac{10^{10}}{10^{10}+1}vaB=\frac{10^{10}+1}{10^{10}+2}\)
c, \(\frac{-1}{4}.x+\frac{3}{7}.x=2\)
d, \(\frac{22}{9}-\left(x+\frac{1}{2}\right)^2=\frac{7}{3}\)
e, \(\left|\frac{1}{4}-x\right|+5\frac{1}{8}=6\frac{1}{8}\)
Bài 12.Tính
a\(-\frac{4}{12}+\frac{6}{7}+\frac{8}{24}\)
b\(\frac{9}{18}+-\frac{7}{12}+\frac{13}{32}\)
c\(\frac{5}{-8}+\frac{14}{25}-\frac{6}{10}\)
d\(\frac{11}{26}+\frac{32}{39}--\frac{14}{52}\)
(câu a là âm\(\frac{4}{12}\); b là âm \(\frac{7}{12}\) ; d là âm\(\frac{14}{52}\))
1. Tìm x biết:
a. ( 4.5 - 2x ) . ( -1\(\frac{4}{7}\)) = \(\frac{11}{14}\)
b. ( 3\(\frac{1}{2}\) - 2x ) . (-3\(\frac{1}{3}\)) = 7\(\frac{1}{3}\)
c. \(\frac{4}{9}\). x =\(\frac{9}{8}\) - 0.125
d.\(\frac{1}{2}\). x + \(\frac{3}{5}\). ( x-2 ) = 3
Bài 1: Thực hiện phép tính bằng cách hợp lí ( nếu có thể )
a, \(-\frac{4}{5}-\frac{8}{25}\left(\frac{-5}{2}-0,125\right)\) c, \(5\frac{1}{2}-4\frac{2}{3}:\frac{16}{9}-3\frac{1}{3}:\frac{16}{9}\) Bài 2: Tìm x, biết
a, \(\left(20\%x+\frac{2}{5}x-2\right):\frac{1}{3}=-2013\) b, \(\left(4,5-2\left|x\right|\right).1\frac{4}{7}=\frac{11}{14}\)
HELP ME!