Question

\(\frac{4}{19}.\frac{-3}{7}+\frac{-3}{7}.\frac{15}{19}+\frac{5}{7}\)

Answer 1

\(\frac{4}{19}\cdot\frac{-3}{7}+\frac{-3}{7}\cdot\frac{15}{19}+\frac{5}{7}\)

\(=\frac{-3}{7}\cdot\left(\frac{4}{19}+\frac{15}{19}\right)+\frac{5}{7}\)

\(=\frac{-3}{7}\cdot1+\frac{5}{7}\)

\(=\frac{-3}{7}+\frac{5}{7}=\frac{2}{7}\)

Answer 2

\(\frac{4}{19}\cdot\frac{-3}{7}+\frac{-3}{7}\cdot\frac{15}{19}+\frac{5}{7}\)

\(=\frac{4}{19}\cdot\frac{-3}{7}+\frac{-3}{7}\cdot\frac{15}{19}+\frac{-5}{3}\cdot\frac{-3}{7}\)

\(=\frac{-3}{7}\left(\frac{4}{19}+\frac{5}{19}+\frac{-5}{3}\right)\)

\(=\frac{-3}{7}.\frac{-68}{57}=\frac{68}{133}\)