Question

\(\frac{2}{3}\)x+\(\frac{1}{2}\)=\(\frac{1}{10}\)

Answer 1

giúp mk với

Answer 2

\(\frac{2}{3}x+\frac{1}{2}=\frac{1}{10}\)

\(\frac{2}{3}x=\frac{1}{10}-\frac{1}{2}\)

\(\frac{2}{3}x=-\frac{2}{5}\)

\(x=-\frac{2}{5}:\frac{2}{3}\)

\(x=-\frac{3}{5}\)

Answer 3

Ta có: \(\frac{2}{3}x+\frac{1}{2}=\frac{1}{10}\)

\(\Rightarrow\frac{2}{3}x=\frac{1}{10}-\frac{1}{2}=-\frac{2}{5}\)

\(\Rightarrow x=-\frac{3}{5}\)

Answer 4

\(\frac{2}{3}x+\frac{1}{2}=\frac{1}{10}\)

\(\frac{2}{3}x=\frac{1}{10}-\frac{1}{2}\)

\(\frac{2}{3}x=\frac{1-5}{10}\)

\(\frac{2}{3}x=-\frac{4}{10}\)

\(x=-\frac{4}{10}\div\frac{2}{3}\)

\(x=-\frac{4}{10}\times\frac{3}{2}\)

\(x=-\frac{3}{5}\)

Answer 5

\(\frac{2}{3}x+\frac{1}{2}=\frac{1}{10}\)

\(\frac{2}{3}x=\frac{1}{10}-\frac{1}{2}=-\frac{2}{5}\)

\(x=\left(-\frac{2}{5}\right):\frac{2}{3}=-\frac{3}{5}\)

Answer 6

\(\frac{2}{3}x+\frac{1}{2}=\frac{1}{10}\)

\(\Rightarrow\frac{2}{3}x=\frac{1}{10}-\frac{1}{2}\)

\(\Rightarrow\frac{2}{3}x=-\frac{2}{5}\)

\(\Rightarrow x=-\frac{2}{5}:\frac{2}{3}\)

\(\Rightarrow x=-\frac{3}{5}\)

Vậy \(x=-\frac{3}{5}\)