Question

\(\frac{21}{36}\cdot\frac{5}{2}-\frac{7}{12}\cdot\frac{2}{7}+\left(2018-2019\right)^0\)

\(-12\frac{1}{3}-\frac{5}{7}+7\frac{1}{3}+1\frac{5}{7}+1^{2019}\)

GIUP MINH VOI!!!!!!

Answer 1

\(a,\frac{21}{36}.\frac{5}{2}-\frac{7}{12}.\frac{2}{7}+\left(2018-2019\right)^0\)

=\(\frac{7}{12}.\frac{5}{2}-\frac{7}{12}.\frac{2}{7}+\left(-1\right)\)

= \(\frac{7}{12}.\left(\frac{5}{2}+\frac{2}{7}\right)+\left(-1\right)\)

=\(\frac{7}{12}.\frac{39}{14}+\left(-1\right)\)

=\(\frac{13}{8}+\left(-1\right)\)

= \(\frac{5}{8}\)

\(b,-12\frac{1}{3}-\frac{5}{7}+7\frac{1}{3}+1\frac{5}{7}+1^{2019}\)

=\(-\frac{37}{3}+\frac{-5}{7}+\frac{22}{3}+\frac{12}{7}+1\)

=\(\left(\frac{-37+22}{3}\right)+\left(\frac{-5+12}{7}\right)+=1\)

= \(-5+1+1\)

=\(-3\)