\(\frac{-4}{7}-x=\frac{3}{5}-2x\)
\(-\frac{4}{7}=\frac{3}{5}-\left(2x-x\right)\)
\(\frac{-4}{7}=\frac{3}{5}-x\)
\(x=\frac{3}{5}+\frac{-4}{7}\)
\(x=\frac{1}{35}\)
Vậy \(x=\frac{1}{35}\)
\(-\frac{4}{7}-x=\frac{3}{5}-2x\\ =>-\frac{4}{7}-\frac{3}{5}\\=-2x+x\\ =>-\frac{41}{35}=-x\\ =>x=\frac{41}{35}\)