Gọi F= 4/2.4+4/4.6+4/6.8+...+4/2008.2010
F/2= 2/2.4+2/4.6+...+2/2008.2010
Mà 2/2.4=1/2-1/4; 2/4.6=1/4-1/6 ....
Vậy F/2= (1/2-1/4)+(1/4-1/6)+....+(1/2008-1/2010)
F/2=1/2-1/2010=2010/4020-2/4020=2008/4...
F= 2008.2/4020=1004/1005
tìm x: 4/2.4 + 4/4.6 +4/6.8...+ 4/x(x+2) = 2011/2013 x > hoặc bằng 2
Bài1:Tính giá trị của biểu thức
a.2/5.1/3-2/15:1/5+3/5.1/3
b.[6+(1/2)3- l-1/2l]:3/12
c.(-1/2)2:1/4-2(-1/2)2
d.F=4/2.4+4/4.6+4/6.8+...+4/2008.2010
e.F=1/18+1/54+1/108+...+1/990
Tính
A = 1.4 + 2.5 + 3.6 + ...+ 99.102
B = 2.4 + 4.6 + 6.8 + ....+ 98.100 + 100.102
BT1: Tính
1) A= \(\dfrac{1}{2.4}+\dfrac{1}{4.6}+\dfrac{1}{6.8}+...+\dfrac{1}{20.22}\)
\(A=\dfrac{6}{2.4}+\dfrac{6}{4.6}+\dfrac{6}{6.8}+\dfrac{6}{8.10}+....+\dfrac{6}{30.32}+\dfrac{6}{32.34}\)
Tính A
Bài 1 : Tính
a) A=\(\dfrac{\dfrac{1}{9}-\dfrac{1}{7}-\dfrac{1}{11}}{\dfrac{4}{9}-\dfrac{4}{7}-\dfrac{4}{11}}\)\(+\dfrac{0,6-\dfrac{3}{25}-\dfrac{3}{125}-\dfrac{3}{625}}{\dfrac{4}{5}-0,16-\dfrac{4}{125}-\dfrac{4}{625}}\)
b)B=\(\dfrac{8}{9}-\dfrac{1}{72}-\dfrac{1}{56}-\dfrac{1}{42}-...-\dfrac{1}{6}-\dfrac{1}{2}\)
c)C=\(\dfrac{1}{1.3}-\dfrac{1}{2.4}+\dfrac{1}{3.5}-\dfrac{1}{4.6}+\dfrac{1}{5.7}-\dfrac{1}{6.8}+\dfrac{1}{7.9}-\dfrac{1}{8.10}\)
1 tiếng nữa mình cần rồi giúp mình nhé !!!!!!!!!! Vạn lời tri ân
Tính tổng: S=\(\dfrac{1}{1.3}\)+\(\dfrac{1}{2.4}\)+\(\dfrac{1}{3.5}\)+\(\dfrac{1}{4.6}\)+...+\(\dfrac{1}{7.9}\)+\(\dfrac{1}{6.8}\)
Tính:
1) (-6 - 2 ) . (-6 + 2 )
2) ( 7 . 3 - 3 ) : (-6)
3) (-5 + 9 ) . (-4 )
4) 72 : (-6 . 2 + 4 )
5) -3 . 7 - 4 . (-5) + 1
6) 18 - 10 : (+2 )- 7
7) 15 : (-5) . (-3) -8
8) (6.8 - 10 : 5) + 3 . (-7)
(Mk cần gấp )
B=2^2/1.3 * 3^2/2.4 * 4^2/3.5 ... 999^2 / 998.1000
