Theo đề bài, ta có:
\(\dfrac{x-2}{4}=\dfrac{5+x}{3}\)
\(\Rightarrow\)\(3.\left(x-2\right)=4.\left(5+x\right)\) (t/c nhân chéo)
\(\Rightarrow\)\(3x-6\) =\(20+4x\)
\(\Rightarrow\) \(-6-20=4x-3x\)
\(\Rightarrow\)\(x=-26\)
\(\dfrac{-3}{4}x\dfrac{4}{7}+\dfrac{-3}{5}x\dfrac{3}{7}-\dfrac{2}{5}\)
\(\left(\dfrac{3}{4}x\dfrac{5}{6}-\dfrac{7}{12}\right)x\left(\dfrac{-12}{7}\right)\)
\(1,4x\dfrac{15}{19}x\left(\dfrac{4}{5}x\dfrac{-2}{3}\right)+\dfrac{7}{15}\)
Tính nha
tìm x
a\(\dfrac{5x-3}{3-2x}=\dfrac{2}{3}\)
b\(\left(\dfrac{4}{5}x+\dfrac{2}{3}\right)\div\dfrac{3}{4}=2\)
c\(\dfrac{3}{4}x-\dfrac{1}{3}=\dfrac{3}{5}\)
d\(\dfrac{2}{3}-\dfrac{3}{5}\div x=\dfrac{1}{4}\)
giúp mình nhé
BT3: Tìm x, biết
3) \(\dfrac{3}{4}.x-\dfrac{5}{3}.x=\dfrac{7}{12}\)
4) \(x-\dfrac{1}{7}=\) \(\dfrac{\dfrac{4}{2011}-\dfrac{4}{2013}+\dfrac{4}{99}}{\dfrac{5}{2011}-\dfrac{5}{2013}+\dfrac{5}{99}}+\dfrac{1}{2}\)
Các bạn giúp mk nhé
a)x=\(\dfrac{1}{4}+\dfrac{2}{13}\)
b)\(\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}\)
c)\(\dfrac{-8}{3}+\dfrac{-1}{3}\le x\le\dfrac{-2}{7}+\dfrac{-5}{7}\)
d)\(\dfrac{-5}{6}+\dfrac{8}{3}\dfrac{29}{-x}\le x\le\dfrac{-1}{2}+2+\dfrac{5}{2}\)
Tìm x, biết:
1. \(\left(\dfrac{2x}{5}+2\right):\left(-4\right)=-1\dfrac{1}{2}\)
2. x. ( x + 1) = 0
3. 2x - 16 = 40 + x
4. x : \(\dfrac{5}{3}\) + \(\dfrac{1}{3}\) = \(\dfrac{-2}{5}\)
5. 3\(\dfrac{1}{2}\) - \(\dfrac{1}{2}\) x = \(\dfrac{2}{3}\)
6. \(\dfrac{x}{4}=\dfrac{9}{x}\)
7. \(\dfrac{1}{3}+\dfrac{1}{2}:x=\) -0,25
tim x , biet :
b, |\(\dfrac{5}{4}\)x-\(\dfrac{7}{2}\)|=|\(\dfrac{5}{8}\)x+\(\dfrac{3}{5}\)|=0
c, |\(\dfrac{7}{5}\)x+\(\dfrac{2}{3}\)|=|\(\dfrac{4}{3}\)x-\(\dfrac{1}{4}\)|
d, |\(\dfrac{7}{8}\)x+\(\dfrac{5}{6}\)|-|\(\dfrac{1}{2}\)x+5|=0
Bài 1. Tính giá trị biểu thức
125%.\((\dfrac{-1}{2})^2\):\((1\dfrac{5}{16}-1,5)+2008^0\)
\(\dfrac{2}{3.5}+\dfrac{2}{5.3}+\dfrac{2}{7.9}+\dfrac{2}{9.11}+\dfrac{2}{11.13}+\dfrac{2}{13.15}\)
Bài 2. Tìm x, biết
x:\(3\dfrac{1}{15}=1\dfrac{1}{12}\)
\(\dfrac{3}{4}.x=27\)
\(x.\dfrac{1}{4}=\dfrac{5}{8}.\dfrac{2}{3}\)
\(\left(x+\dfrac{1}{4}\right):\dfrac{3}{7}=\dfrac{1}{6}\)
\(\dfrac{3}{4}-2.|2x-\dfrac{2}{3}|=2\)
\(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{2}\)
bài 1: tìm x bt:
a\(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
b, \(5\dfrac{4}{7}:x=13\)
c, (2 và 4/5.x-50) :2/3= 51
d,\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
e, \(\dfrac{2}{3}-\dfrac{1}{2}x=\dfrac{5}{12}\)
giúp mk nhs!!!!!!!!!!
Bài 1 : Tìm x
a) 4\(\dfrac{1}{2}\)x : \(\dfrac{5}{12}\)=0,5 b)1,5+1\(\dfrac{1}{4}\).x= \(\dfrac{2}{3}\) c) 7,5.1\(\dfrac{3}{4}\)=\(6\dfrac{2}{5}\) d)(x - 5):\(\dfrac{1}{3}\)=\(\dfrac{2}{5}\) e) (4,5-2x):\(\dfrac{3}{4}\)=1\(\dfrac{1}{3}\) f) (2,7x - 1\(\dfrac{1}{2}\)x) : \(\dfrac{2}{7}=\dfrac{-21}{7}\)
Bài 2 : tìm a,b biết
\(\dfrac{a}{27}=\dfrac{-5}{9}=\dfrac{-45}{b}\)
1. Tim x:
a. \(\dfrac{x}{5}\) = \(\dfrac{5}{6}\) + \(\dfrac{-19}{30}\)
b. \(\dfrac{-5}{6}\) \(-x\) = \(\dfrac{7}{12}\)\(-\) \(\dfrac{1}{3}\)\(\times\) \(x\)
c.2016\(^{^{ }3}\) \(\times\)2016\(^{^{ }x}\) = 2016\(^{^{ }8}\)
d. \((x+\dfrac{3}{4}):\dfrac{5}{2}=3^1_2\)
e. (2,8 \(x\) \(-\) 2\(^5\)) : \(\dfrac{2}{3}=3^2\)
f. \(\dfrac{4}{7}\times x-\dfrac{2}{3}=\dfrac{2}{5}\)
g. \((\dfrac{3x}{7}+1):\left(-4\right)=\dfrac{-1}{28}\)
2. Thuc hien phep tinh:
a. \(\dfrac{1}{2}+\dfrac{1}{2}\times\dfrac{2}{3}-\dfrac{1}{3}:\dfrac{3}{4}+1^4_5\)
b. \(\dfrac{7\times5^2-7^2}{7\times24+21}\)
c. \(\dfrac{2}{3}+\dfrac{1}{3}\times(-\dfrac{4}{9}+\dfrac{5}{6}):\dfrac{7}{12}\)
