Question

\(\dfrac{\left(\dfrac{8^2}{128}+\dfrac{3}{4}\right):1\dfrac{3}{16}}{1\dfrac{11}{19}}\)

Answer 1

\(\dfrac{\left(\dfrac{8^2}{128}+\dfrac{3}{4}\right)\div1\dfrac{3}{16}}{1\dfrac{11}{19}}\)

\(=\dfrac{\left(\dfrac{64}{128}+\dfrac{3}{4}\right)\div\dfrac{19}{16}}{\dfrac{30}{19}}\)

\(=\dfrac{\left(\dfrac{1}{2}+\dfrac{3}{4}\right)\times\dfrac{16}{19}}{\dfrac{30}{19}}\)

\(=\dfrac{5}{4}\times\dfrac{16}{19}\div\dfrac{30}{19}\)

\(=\dfrac{5}{4}\times\dfrac{16}{19}\times\dfrac{19}{30}\)

\(=\dfrac{5\times16}{4\times30}=\dfrac{4}{6}=\dfrac{2}{3}\)

Answer 2

Cái này bạn dùng máy tính nhé