\(\dfrac{\dfrac{1}{2}}{\dfrac{1}{3}x}=\dfrac{3}{4}\)
\(3.\dfrac{1}{3}x=4.\dfrac{1}{2}\)
\(x=2\)
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Tìm x biết :
1/dfrac{4}{3} + x dfrac{2}{15} 2/dfrac{1}{3}+dfrac{1}{2}: x -0,25 3/(dfrac{2x}{5}+2 ):(-4) -1dfrac{1}{2} 4/ x.( x + 1) 0 5/3dfrac{1}{2}-dfrac{1}{2}x dfrac{2}{3}
6/1dfrac{1}{2}+xdfrac{3}{2}-7 7/2x-1640+x 8/x:dfrac{5}{3}+dfrac{1}{3}dfrac{-2}{5} 9/dfrac{x}{4}dfrac{9}{x}
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Tìm x biết :
1/\(\dfrac{4}{3}\) + x = \(\dfrac{2}{15}\) 2/\(\dfrac{1}{3}+\dfrac{1}{2}:\) x = -0,25 3/(\(\dfrac{2x}{5}+2\) ):(-4) = -1\(\dfrac{1}{2}\) 4/ x.( x + 1) = 0 5/3\(\dfrac{1}{2}-\dfrac{1}{2}x\) = \(\dfrac{2}{3}\)
6/1\(\dfrac{1}{2}+x=\dfrac{3}{2}-7\) 7/\(2x-16=40+x\) 8/\(x:\dfrac{5}{3}+\dfrac{1}{3}=\dfrac{-2}{5}\) 9/\(\dfrac{x}{4}=\dfrac{9}{x}\)
tìm x:
a)\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
b) \(\left(x.6\dfrac{2}{7}+\dfrac{3}{7}\right).2\dfrac{1}{5}-\dfrac{3}{7}=-2\)
c) \(x.3\dfrac{1}{4}+\left(\dfrac{-7}{6}\right).x-1\dfrac{2}{3}=\dfrac{5}{12}\)
d) \(5\dfrac{8}{17}:x+\left(-\dfrac{4}{17}\right):x+3\dfrac{1}{7}:17\dfrac{1}{3}=\dfrac{4}{11}\)
a, \(\dfrac{5}{2}-3\left(\dfrac{1}{3}-x\right)=\dfrac{1}{4}-7x\)
b,\(60\%.x+\dfrac{2}{3}.x=\dfrac{1}{3}.6\dfrac{1}{3}\)
c, \(\left(\dfrac{9}{2}.x-2x\right).\left(-1\dfrac{4}{7}\right)=\dfrac{11}{4}\)
d,\(\left(x+\dfrac{5}{6}\right).2\dfrac{2}{5}-1\dfrac{1}{4}=35\%\)
21 tháng 8 2017 lúc 15:37
a\(\dfrac{5}{6}x-\dfrac{2}{3}=3\dfrac{1}{2}\)
b\(\dfrac{4}{5}-\dfrac{3}{4}\div x=0,3\)
c\(\dfrac{-3}{2}-\dfrac{1}{4}x=1\dfrac{1}{3}-0,2x\)
d\(\left|\dfrac{3}{5}x+\dfrac{4}{3}\right|:\dfrac{2}{3}-0,5=1\dfrac{1}{2}\)
e\(\dfrac{4x-5}{2-3x}=\dfrac{3}{4}\)
giúp mình nhé
dfrac{-2}{3}.x+dfrac{1}{5}dfrac{3}{10}
dfrac{1}{3}+dfrac{2}{3}:x-7
60%xdfrac{1}{3}.6dfrac{1}{3}
left(2x+dfrac{3}{2}right)^2-dfrac{9}{25}0
60%x+0,4x+x:2
left(dfrac{2}{3}-xright):dfrac{3}{4}dfrac{1}{5}
-2x-dfrac{-3}{5}:left(-0,5right)^2-1dfrac{1}{4}
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\(\dfrac{-2}{3}.x+\dfrac{1}{5}=\dfrac{3}{10}\)
\(\dfrac{1}{3}+\dfrac{2}{3}:x=-7\)
\(60\%x=\dfrac{1}{3}.6\dfrac{1}{3}\)
\(\left(2x+\dfrac{3}{2}\right)^2-\dfrac{9}{25}=0\)
\(60\%x+0,4x+x:=2\)
\(\left(\dfrac{2}{3}-x\right):\dfrac{3}{4}=\dfrac{1}{5}\)
\(-2x-\dfrac{-3}{5}:\left(-0,5\right)^2=-1\dfrac{1}{4}\)
tìm x biết
a) \(\dfrac{2x-3}{3}+-\dfrac{3}{2}=\dfrac{5-2x}{6}-\dfrac{1}{2}\)
b) \(\left(3x-\dfrac{1}{2}\right).\left(3-\dfrac{1}{2}x\right).\left(1+\dfrac{3}{4}:x\right)=0\)
c) \(\left(3-\dfrac{9}{10}-|x+2|\right):\left(\dfrac{19}{20}-1-\dfrac{2}{3}\right)+\dfrac{4}{5}=1\)
Bài 1:
a) \(\left[\dfrac{3}{20}-\dfrac{1}{5}x\right].1\dfrac{2}{3}=1\dfrac{1}{4}\)
b)\(\dfrac{-2}{3}.x+\dfrac{1}{5}=\dfrac{3}{10}\)
c)\(\dfrac{-2}{3} \)-\(\dfrac{1}{3}\left(2x-7\right)=\dfrac{3}{2}\)
tìm x
\([\dfrac{6:\dfrac{3}{5}-1\dfrac{1}{16}.\dfrac{16}{7}}{4\dfrac{1}{5}-\dfrac{10}{11}+5\dfrac{2}{11}}-\dfrac{\left(\dfrac{3}{20}+\dfrac{1}{2}-\dfrac{1}{5}\right).\dfrac{12}{49}}{3\dfrac{1}{3}+\dfrac{2}{9}}].x=2\dfrac{23}{96}\)
\(a,-\dfrac{2}{3}.\left(x-\dfrac{1}{4}\right)=\dfrac{1}{3}.\left(2x-1\right)\)
\(b,\dfrac{1}{5}.2^x+\dfrac{1}{3}.2^{x+11}=\dfrac{1}{5}.2^7+\dfrac{1}{3}.2^8\)
\(c,\dfrac{x-19}{345}+\dfrac{x-20}{346}=\dfrac{x-1}{347}+\dfrac{x-22}{348}\)
tìm x biết
left(3dfrac{1}{2}+2xright).2dfrac{2}{3}5dfrac{1}{3}
dfrac{3}{4}-2.left|2x-dfrac{2}{3}right|2
left(0.6-dfrac{1}{2}right).dfrac{3}{4}-left(-1right)dfrac{1}{3}
left(3x-1right).left(-dfrac{1}{2}x+5right)0
dfrac{1}{4}+dfrac{1}{3}:left(2x-1right)-5
left(2x+dfrac{3}{5}right)^2-dfrac{9}{25}0
-5.left(x+dfrac{1}{5}right)-dfrac{1}{2}.left(x-dfrac{2}{3}right)dfrac{3}{2}x-dfrac{5}{6}
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tìm x biết
\(\left(3\dfrac{1}{2}+2x\right).2\dfrac{2}{3}=5\dfrac{1}{3}\)
\(\dfrac{3}{4}-2.\left|2x-\dfrac{2}{3}\right|=2\)
\(\left(0.6-\dfrac{1}{2}\right).\dfrac{3}{4}-\left(-1\right)=\dfrac{1}{3}\)
\(\left(3x-1\right).\left(-\dfrac{1}{2}x+5\right)=0\)
\(\dfrac{1}{4}+\dfrac{1}{3}:\left(2x-1\right)=-5\)
\(\left(2x+\dfrac{3}{5}\right)^2-\dfrac{9}{25}=0\)
\(-5.\left(x+\dfrac{1}{5}\right)-\dfrac{1}{2}.\left(x-\dfrac{2}{3}\right)=\dfrac{3}{2}x-\dfrac{5}{6}\)