= \(\dfrac{2}{5}x\dfrac{5}{8}=\dfrac{2}{8}=\dfrac{1}{4}\)
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Các câu hỏi tương tự
Tìm \(x\)
1. \(\dfrac{1}{7}=\dfrac{8}{-x}\)
2. \(\dfrac{3x}{9}=\dfrac{2}{6}\)
3. \(4\dfrac{2}{5}:\left(\dfrac{-33}{10}\right)+x=-1\dfrac{5}{6}\)
4. \(45\%.x-2\dfrac{3}{8}=-1\dfrac{31}{40}\)
5. \(\left(x-2\dfrac{1}{4}\right):\left(-\dfrac{5}{6}\right)=3\)
\(\dfrac{-4}{8}\) - ( \(\dfrac{-1}{3}\) - x ) = \(\dfrac{2}{5}\)
\(x-\dfrac{1}{5}=\dfrac{3}{4}\)
\(\dfrac{2}{5}x+\dfrac{1}{4}=\dfrac{1}{8}\)
Tìm các số nguyên ,biết :
a)\(\dfrac{4+x}{x+2}=\dfrac{8}{6}\)
b)\(\dfrac{3}{x-5}=\dfrac{-4}{x+2}\)
c)\(\dfrac{x}{-2}=\dfrac{-8}{x}\)
CMR : \(\dfrac{2}{5}< A< \dfrac{8}{9}\)
Với \(A=\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+\dfrac{1}{5^2}+\dfrac{1}{6^2}+\dfrac{1}{7^2}+\dfrac{1}{8^2}+\dfrac{1}{9^2}\)
\(\dfrac{5}{9}\).\(\dfrac{2}{7}\)+\(\dfrac{5}{9}\).\(\dfrac{5}{7}\) - \(\dfrac{8}{3}\)
tìm x,y thuộc z
a. \(\dfrac{-1}{4}:\dfrac{-3}{4}+\dfrac{1}{2}< x< \dfrac{7}{8}-\dfrac{1}{2}:\dfrac{-5}{6}\)
Câu hỏi today là a, \(\dfrac{1}{5\cdot8}+\dfrac{1}{8\cdot11}+...+\dfrac{1}{x+\left(x+1\right)}=\dfrac{101}{1540}\)
b,\(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{x+\left(x+1\right)}=\dfrac{2020}{2021}\)
Chúc các bn học tốt ❤
-8 : (4\(\dfrac{1}{5}\) x + \(\dfrac{3}{10}\) ) = -4\(\dfrac{4}{5}\)