Question

Đ, S?

Answer 1

Đặt tính rồi tính ta có:

\(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{435}\\{\,\,58}\end{array}}\\\hline{\,\,\,493}\end{array}\)                                    \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{547}\\{\,\,39}\end{array}}\\\hline{\,\,\,408}\end{array}\)

\(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{358}\\{214}\end{array}}\\\hline{\,\,\,\,572}\end{array}\)                                   \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{629}\\{258}\end{array}}\\\hline{\,\,\,371}\end{array}\)

Answer 2