Question

Cho \(A=\dfrac{2016.2017-2}{2015+2015.2017},B=\dfrac{-2016.20172017}{20162016.2017}\)

Tinh A+B

Answer 1

A = 1

B = -1

=> A + B = 0

Answer 2

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Answer 3

Ta có : A =\(\dfrac{2016.2017-2}{2015+2015.2017}=\dfrac{2016.2017-2}{\left(2017-2\right)+2015.2017}\)

=\(\dfrac{2016.2017-2}{2017+2015.2017-2}=\dfrac{2016.2017-2}{2017\left(2015+1\right)-2}\)

=1

-- B =\(\dfrac{-2016.20172017}{20162016.2017}=\dfrac{-2016.10001.2017}{10001.2016.2007}=-1\)

=> A+B = -1 + 1 =0