Lời giải:
$B=\frac{10^{11}+10}{10^{12}+10}$
Đặt $10^{11}-1=a; 10^{12}-1=b$ thì $0< a< b$. Khi đó:
$A-B=\frac{a}{b}-\frac{a+11}{b+11}=\frac{11(a-b)}{b(b+11)}<0$
$\Rightarrow A< B$
Lời giải:
$B=\frac{10^{11}+10}{10^{12}+10}$
Đặt $10^{11}-1=a; 10^{12}-1=b$ thì $0< a< b$. Khi đó:
$A-B=\frac{a}{b}-\frac{a+11}{b+11}=\frac{11(a-b)}{b(b+11)}<0$
$\Rightarrow A< B$
so sánh
1) A = \(\dfrac{10^{11}-1}{10^{12}-1}\) và B =\(\dfrac{10^{10}+1}{10^{11}+1}\)
2) A = \(\dfrac{2018^9+1}{2018^{10}-1}\) và B = \(\dfrac{2018^{19}+1}{2018^{20}+1}\)
3) A = \(\dfrac{2018^{19}+1}{2018^{20}+1}\) và B = \(\dfrac{2018^{20}+1}{2018^{21}+1}\)
1:Tính
a) \(\left(\dfrac{1}{7}.x-\dfrac{2}{7}\right).\left(\dfrac{-1}{5}.x-\dfrac{2}{5}\right)=0\)
b) \(\dfrac{1}{6}.x+\dfrac{1}{10}.x-\dfrac{4}{5}.x+1=0\)
2:So sánh:
a) A=\(\left(\dfrac{-46}{51}.0,32.\dfrac{17}{20}\right):\dfrac{64}{75}\)
B=\(\dfrac{-10}{11}.\dfrac{8}{9}+\dfrac{7}{8}.\dfrac{10}{11}\)
b) A=\(\dfrac{-1}{3}+\dfrac{0,2-0,375+\dfrac{5}{11}}{-0,3+\dfrac{9}{16}-\dfrac{15}{22}}\)
B=\(\dfrac{-43}{51}.\dfrac{19}{80}\)
Bài1Chứng minh a )A=\(\dfrac{m}{n}=1+\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{10}\notin N\)
B=\(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{81}\notin N\)
b) Cho \(\dfrac{m}{n}=1+\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{10}\)
Chứng minh m \(⋮\) 11
Cho hai phân số \(A=\dfrac{10^{19}+1}{10^{20}+1}\);\(B=\dfrac{10^{20}+1}{10^{21}+1}\). So sánh A và B
a) (\(\dfrac{11}{12}+\dfrac{11}{12.23}+\dfrac{11}{23.34}+....+\dfrac{11}{89.100}\))+ x =\(\dfrac{5}{3}\)
b) (\(\dfrac{5}{11.16}+\dfrac{5}{16.21}+...+\dfrac{5}{19.24}\))- x + \(\dfrac{1}{3}=\dfrac{7}{3}\)
c) \(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{10}+...+\dfrac{2}{x\left(x+1\right)}=\dfrac{1999}{2001}\)
Giúp mình nhé mấy bạn. Mai mình phải nộp rùi. Ai làm nhanh mình tick cho nha
So sánh :
\(A=\dfrac{10^8+2}{10^8-1}\) và \(B=\dfrac{10^8}{10^8-3}\)
So sánh:\(\dfrac{10^{2011}+1}{10^{2012}+1}và\dfrac{10^{2010}+1}{10^{2011}+1}\)
Thực hiện phép tính ( tính nhanh nếu có thể )
a, -5/21 + -2/21 + 8/24
b, 4/11 . -2/7 + 4/11 . -4/7 + 4/11 . -1/7
c, \(10\dfrac{5}{9}\) - ( \(3\dfrac{5}{7}\) + \(4\dfrac{5}{9}\) )
d, 1/3 + \(1\dfrac{3}{4}\) - ( \(1\dfrac{3}{4}\) - 80% )
e, \(5\dfrac{3}{5}\) + \(7\dfrac{21}{48}\) : 10/7 - \(5\dfrac{21}{48}\) : 10/7
f, -5/7 . 2/11 - 5/11 . 9/7 + \(2\dfrac{5}{7}\)
g, -3/13 . 6/8 + 7/13 . -3/8 + \(1\dfrac{3}{8}\)
Tính giá trị biểu thức :
\(\dfrac{6:\dfrac{3}{5}-1\dfrac{1}{6}\cdot\dfrac{6}{7}}{4\dfrac{1}{5}\cdot\dfrac{10}{11}+5\dfrac{2}{11}}\).