Bài làm
Ta có : A = \(^{2017^2}\)=2017.2017=2017.(2016+1)=2017.2016+2017
B = 2016.2018 = 2016.(2017+1)=2016.2017+2016
Vì 2017>2016\(\Rightarrow\) 2017.2016+2017>2016.2017+2016
\(\Rightarrow\) A>B
Vậy A > B
B = 2016 . 2018
= (2017 - 1) . (2017 + 1)
= 2017 . (2017 + 1) - (2017 + 1)
= 20172 + 2017 - 2017 - 1
= 20172 - 1
Vì 20172 - 1 < 20172 nên B < A
Vậy, A > B