Question

cho 3 so nguyen abc thoa man a+b=-4, b+c=-6,c+b=12

Answer 1

\(a+b=-4;b+c=-6;a+c=12\)

\(\Rightarrow a+b+b+c+a+c=\left(-4\right)+\left(-6\right)+\left(-12\right)=2\)

\(\Rightarrow2a+2b+2c=2\)

\(\Rightarrow\left(a+b+c\right)\cdot2=2\)\(\Rightarrow a+b+c=1\)

\(Do:\) \(a+b=-4\)

\(\Rightarrow a+b+c=\left(-4\right)+c=1\)

\(\Rightarrow c=5\)

Vì: \(a+c=12\)

\(\Rightarrow a+b+c=12+b=1\)

\(\Rightarrow b=-11\)

Và: \(b+c=-6\)

\(\Rightarrow a+b+c=a+\left(-6\right)=1\)

\(\Rightarrow a=7\)

\(\Rightarrow a=7;b=-11;c=5\)

Vậy: \(a=7;b=-11;c=5\)