Ta có: \(\dfrac{-1}{4}+\dfrac{7}{33}+\dfrac{-5}{3}+\dfrac{5}{12}+\dfrac{-6}{11}+\dfrac{48}{49}\)
= \(\dfrac{-3}{12}+\dfrac{7}{33}+\dfrac{-20}{12}+\dfrac{5}{12}+\dfrac{-18}{33}+\dfrac{48}{49}\)
= \(\left(\dfrac{-3}{12}+\dfrac{-20}{12}+\dfrac{5}{12}\right)+\left(\dfrac{7}{33}+\dfrac{-18}{33}\right)+\dfrac{48}{49}\)
= \(-\dfrac{3}{2}-\dfrac{1}{3}\)+\(\dfrac{48}{49}\)
= \(\dfrac{-251}{294}\)