Ta có:
-125=-53
suy ra 3x2-32=-5
3x2=-5+32
3x2=27
x2=27:3
x2=9
x2=32
x=3
Vậy x=3
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Các câu hỏi tương tự
BT1: Tìm x, biết:
7) \(\left(\dfrac{2}{3}-\dfrac{3}{5}x\right)^3=\dfrac{-64}{125}\)
BT1: Tìm x, biết:
2) \(\left(x-3^2\right)^3=\left(3^3\right)^2\)
BT1: Tìm x, biết:
2) \(\left(x+\dfrac{3}{5}\right)^2+1\dfrac{16}{25}=9\%:4,5\%\)
Tìm số nguyên x
1/ 17x+3left(-16x-37right)2x+43-4x
2/ -2x-3left(x-17right)34-2left(-x+25right)
3/ left{-3x+2left[45-x-3left(3x+7right)-2xright]+4xright}55-103-57:left[-2left(2x-1right)^2-left(-9right)^0right]-106
4/ -2x+3left{12-2left[3x-left(20+2xright)-4xright]+1right}45
5/ 3x-32-5+1
6/ 15+4x 2x-145
7/ -3left(2x+5right)-16 -4left(3-2xright)
8/ -2x+15 3x-7 19-x
Đọc tiếp
Tìm số nguyên x
1/ \(17x+3\left(-16x-37\right)=2x+43-4x\)
2/ \(-2x-3\left(x-17\right)=34-2\left(-x+25\right)\)
3/ \(\left\{-3x+2\left[45-x-3\left(3x+7\right)-2x\right]+4x\right\}=55-103-57:\left[-2\left(2x-1\right)^2-\left(-9\right)^0\right]=-106\)
4/ \(-2x+3\left\{12-2\left[3x-\left(20+2x\right)-4x\right]+1\right\}=45\)
5/ \(3x-32>-5+1\)
6/ \(15+4x< 2x-145\)
7/ \(-3\left(2x+5\right)-16< -4\left(3-2x\right)\)
8/ \(-2x+15< 3x-7< 19-x\)
BT1: Tìm x, biết
1) \(\dfrac{-2}{5}+\dfrac{5}{3}.\left(\dfrac{3}{2}-\dfrac{4}{15}x\right)=\dfrac{-7}{6}\)
BT1: Tìm x, biết:
4) \(\dfrac{\left(x+1\right)^2}{2}=\dfrac{4}{x+1}\)
Tìm x,y biết:
a) \(-\dfrac{1}{2}\left(3-2x\right)-7=5-\dfrac{1}{3}\left(x-\dfrac{4}{5}\right)\)
b)\(\left(5-\dfrac{3x}{2}\right):-1\dfrac{3}{8}=-7\dfrac{1}{3}\)
c)\(\left(2+3x\right)^2+\left|3x+2y\right|=0\)
tìm x biết :
a) \(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
b) \(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
c) \(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
Tìm x,y,z
\(\left(x-1\right)^2+\left(3x-y-3\right)^2+\left(y+z\right)^4=0\)